Answer:
6
Explanation:
The atom number 6 is the carbon. To calculate the number of neutron you need to substract the atomic weight and the number of the atom. The weight is 12 and the number is 6 so 12-6 equal 6 equal to the number of proton
The scale will read <u>112 grams.</u>
Why?
Since we already know the percent error of the scale (12%) and we also know the mass of the block that is placed on the scale, we can calculate what will be the read of the scale by using the following formula:
![ScaleRead=100g+(100g*\frac{12}{100})=100g+(100g*0.12)=100g+12g\\\\ScaleRead=112g](https://tex.z-dn.net/?f=ScaleRead%3D100g%2B%28100g%2A%5Cfrac%7B12%7D%7B100%7D%29%3D100g%2B%28100g%2A0.12%29%3D100g%2B12g%5C%5C%5C%5CScaleRead%3D112g)
We can see that the scale will read 112 grams.
Let's verify that we are right by using the following formula to verify if the obtained value for the scale read will be 12%:
![PercentError=\frac{ActualValue-RealValue}{RealValue}*100=\frac{112g-100g}{100g}*100\\\\PercentError=\frac{12g}{100g}*100=0.12*100=12(percent)](https://tex.z-dn.net/?f=PercentError%3D%5Cfrac%7BActualValue-RealValue%7D%7BRealValue%7D%2A100%3D%5Cfrac%7B112g-100g%7D%7B100g%7D%2A100%5C%5C%5C%5CPercentError%3D%5Cfrac%7B12g%7D%7B100g%7D%2A100%3D0.12%2A100%3D12%28percent%29)
Hence, we can see that the scale will read <u>112 grams.</u>
Have a nice day!
Answer:
which of these elements has the chesmistry
The question is incomplete, the complete question is:
Standardization of a Borax solution (Na2B4O7). A student titrates a 20.00 mL sample of an aqueous borax solution with 1.044 M H2SO4. It takes 2.63 mL of acid to reach the equivalence point. Knowing it takes 1 H2SO4 to neutralize 2 Na2B4O7, what was the concentration of this Borax solution?
<u>Answer: </u>The concentration of borax solution is 0.069 M.
<u>Explanation:</u>
To calculate the concentration of borax solution, the formula used is:
....(1)
where,
are the n-factor, concentration and volume of sulfuric acid
are the n-factor, concentration and volume of borax solution.
We are given:
![n_1=1\\C_1=1.044M\\V_1=2.63mL\\n_2=2\\C_2=?M\\V_2=20mL](https://tex.z-dn.net/?f=n_1%3D1%5C%5CC_1%3D1.044M%5C%5CV_1%3D2.63mL%5C%5Cn_2%3D2%5C%5CC_2%3D%3FM%5C%5CV_2%3D20mL)
Putting values in equation 1, we get:
![1\times 1.044\times 2.63=2\times C_2\times 20\\\\C_2=\frac{1\times 1.044\times 2.63}{2\times 20}\\\\C_2=0.069M](https://tex.z-dn.net/?f=1%5Ctimes%201.044%5Ctimes%202.63%3D2%5Ctimes%20C_2%5Ctimes%2020%5C%5C%5C%5CC_2%3D%5Cfrac%7B1%5Ctimes%201.044%5Ctimes%202.63%7D%7B2%5Ctimes%2020%7D%5C%5C%5C%5CC_2%3D0.069M)
Hence, the concentration of borax solution is 0.069 M.
Answer: 18
Explanation:
18 because that is the max