Answer:
The object is moving away from the origin
The object started at 2 meters
The object is traveling at a constant velocity
Explanation:
Answer:
<u>1092K</u>
Explanation:
We can use the combined gas law to answer this question:
P1V1/T1 = P2V2/T2,
where P, V and T are the Pressure, Volume, and Temperature for initial (1) and Final (2) conditions. Temperatures must be in Kelvin.
The problem states that V2 = 2V1 and P2 = 2P1.
Let's rearrange to solve for T2, which is the question:
T2 = T1(P2/P1)(V2/V1)
Note how the pressure and temperature values are written: as ratios. Enter the values:
T2 = (273K)(P2/P1)(V2/V1)
T2 = (273K)(2P1/P1)(2V1/V1) [Use the expressions for V2 and P2 from above]
T2 = (273K)(2)(2)
T2 = 1092K
Let's assume that CH₄ has ideal gas behavior.
Then we can use ideal gas formula,
PV = nRT
Where, P is the pressure of the gas (Pa), V is the volume of the gas (m³), n is the number of moles of gas (mol), R is the universal gas constant ( 8.314 J mol⁻¹ K⁻¹) and T is temperature in Kelvin.
P = 1 atm = 101325 Pa
V = 1.50 L = 1.50 x 10⁻³ m³
n = ?
R = 8.314 J mol⁻¹ K⁻¹
T = 0 °C = 273 K
By substitution,
101325 Pa x 1.50 x 10⁻³ m³ = n x 8.314 J mol⁻¹ K⁻¹ x 273 K
n = 0.0669 mol
Hence, moles of CH₄ = 0.0669 mol
Moles = mass / molar mass
Molar mass of CH₄ = 16 g mol⁻¹
Mass of CH₄ = moles x molar mass
= 0.0669 mol x 16 g mol⁻¹
= 1.0704 g
Hence, mass of CH₄ in 1.50 L at STP is 1.0704 g
Answer is: <span>pH of the water is 8.33, this is basic solution (pH is greater than seven).
</span>[H₃O+] = 4.60·10⁻⁹ M; equilibrium concentration of hydronium ion.
pH = -log[H₃<span>O+].
</span>pH = -log(4.60·10⁻⁹ M).
pH = 8.33.
pH (potential of
hydrogen) is a numeric scale used to specify the acidity or basicity <span>an aqueous
solution.
</span><span>
</span>
Answer:
1.80 x 10^24 atoms
Explanation:
3moles × 6.022×10^23 atoms/mole