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vlabodo [156]
2 years ago
14

Find the GFC of 16 and 80

Mathematics
1 answer:
Dima020 [189]2 years ago
5 0

Answer:

It is 16

Step-by-step explanation:

Hope this helped have an amazing day/month/year!

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6a+35/15a is your answer

5 0
3 years ago
Which fraction is equal to 0.8? Express your answer in simplest form. A. 3/5 B. 4/5 C. 1/8 D. 5/8
Murrr4er [49]
0.8 = 0.8 \times \frac{10}{10} = \frac{8}{10} =\frac{4\times 2}{5\times 2} = \boxed{\bf{\frac{4}{5}}}

Answer is B
4 0
3 years ago
Use rounding or compatible numbers to estimate the sum 271 + 425
zysi [14]

Answer:

700

Step-by-step explanation:

For this one I'll do estimates. 271 estimated would drop down to 270. And 425 would bump up to 430. Adding 270 and 400 you would get a round number of 700!

Hope this helped.

4 0
3 years ago
Read 2 more answers
You take a quiz with 6 multiple choice questions. After you studied your estimated that you would have about an 80 % chance of g
Arada [10]

Answer:

1.15%

Step-by-step explanation:

To get the probability of m  independent events you multiply the individual probability of each event. In this case we have m independent events, each one with the same probability, therefore:

p^{m}

0.8^{20} = 1.15\%

This is a particlar scenario of binomial distribution problem. So the binomial distribution questions are about the number of success of m independent events, where every individual event has the same p probability. In the question we have 20 events and each event has a probability of 80%. The binomial distribution formula is:

\binom{n}{k} * p^{k} * (1-p)^{n-k}

n is the number of events

k is the number of success

p is the probability of each individual event

\binom{n}{k} is the binomial coefficient

the binomial coefficient allows to find the subsets of k elements in a set of n elements.  In this case there is only one subset possible since the only way to get 20 of 20 correct questions is to getting right all questions (for getting 19 of 20 questions there are many ways, for example getting the first question wrong and all the other questions right, or getting second questions wrong and all the other questions right, etc).

\binom{n}{k} = \frac{n!}{k!(n-k)!}

therefore, for this questions we have:

\frac{20!}{20!(20-20)!} * 0.8^{20} * (1-0.8)^{0} = 1.15\%

4 0
3 years ago
1.4.7+4.7.10+7.10.13 to n terms
Cerrena [4.2K]
◆ SEQUENCE AND SERIES ◆

Heya !

Check the attachment.
Hope it helps you ;)

8 0
3 years ago
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