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3 years ago

Step by step 5p-14=8p+4

Mathematics

2 answers:

zheka24 [161]3 years ago

8 0

5p-8p=14+4
-3p=18
P=-6

Check it

5(-6)-14= 8(-6)+4
-30-14=-48+4
-44=-44

frutty [35]3 years ago

6 0

5p-14=8p+4
add 14 on both sides
5p-14+14=8p+4+14
5p=8p+18
subtract 8p from both sides
5p-8p=8p-8p+18
-3p=18
divede both sides by -3
-3p/-3=18/-3
p=-6

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Find the volume of the cone. Either enter an exact answer in terms of \piπpi or use 3.143.143, point, 14 for \piπpi and round yo

NeTakaya

Answer:

Volume of the cone = 130.83 cubic units

Step-by-step explanation:

The question us incomplete without the diagram of the cone and it's dimensions as this would enable us get the exact answer.

Find attached the diagram used in solving the solution.

Volume of cone = ⅓ πr²h

Radius = r = 5 unit

Height = h = 5 unit

π = 3.14

By inserting the values of each variables, we have:

Volume of cone = ⅓ × 3.14× (5)² × 5

= ⅓ × 3.14× 25×5 = ⅓ × 3.14×125

Volume of cone = (392.5)/3

Volume of cone = 130.8333

Volume of cone = 130.83 cubic units (to the nearest hundredth)

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3 years ago

Please help @musiclover10045<br> I have been stuck on this problem like forever

Stella [2.4K]

a) ABD and CBD are Supplementary angles and need to equal 180 degrees

Subtract 117 from 180 for CBD:

CBD = 180 - 117 = 63 degrees

b) In triangles the the shortest side would be opposite the shortest angle.

Since angle D is 56 degrees ( the smallest inside angle) then side BC would be the shortest side.

c) The side opposite the largest angle would be the longest.

Angle B is 63 degrees ( the largest) so side CD is the longest.

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3 years ago

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DanielleElmas [232]

Answer:

Step-by-step explanation:

Given expression is,

$\text{cot}A=\frac{1}{2}(\text{cot}\frac{A}{2}-\text{tan}\frac{A}{2})$

To prove this identity we will take the right side of the identity,

$\frac{1}{2}(\text{cot}\frac{A}{2}-\text{tan}\frac{A}{2})=\frac{1}{2}(\frac{1}{\text{tan}\frac{A}{2}}-tan\frac{A}{2})$

$=\frac{1}{2}(\frac{1-\text{tan}^2\frac{A}{2}}{tan\frac{A}{2}})$

$=\frac{1}{2}[\frac{2(1-\text{tan}^2\frac{A}{2})}{2tan\frac{A}{2}}]$

$=\frac{1}{2}(\frac{2}{\text{tan}A} )$ [Since $\text{tan}A=\frac{2\text{tan}\frac{A}{2}}{1-\text{tan}^2\frac{A}{2}}$ ]

= cot A

Hence right side of the equation is equal to the left side of the equation.

3 0

3 years ago

Find the length of the curve y = 3/5x^5/3 - 3/4x^1/3 + 6 for 1 < = x < = 8. The length of the curve is . (Type an exact an

Mashutka [201]

Answer:

$\sqrt\frac{387}{20}$

Step-by-step explanation:

$Arc Length =\int\limits^a_b {\sqrt{1+(\frac{dy}{dx})^2 } } \, dx$

$y=\dfrac{3}{5}x^{\frac{5}{3}}- \dfrac{3}{4}x^{\frac{1}{3}}+6$

$\frac{dy}{dx} =x^{\frac{2}{3}}-\dfrac{1}{4}x^{-\frac{2}{3}}$

$1+(\frac{dy}{dx})^2 }=1+(x^{\frac{2}{3}}-\dfrac{1}{4}x^{-\frac{2}{3}})^2\\=1+(x^{\frac{4}{3}}-\dfrac{1}{2}+ \dfrac{1}{16}x^{-\frac{4}{3}})$

$=\dfrac{1}{2}+x^{\frac{4}{3}}+ \dfrac{1}{16}x^{-\frac{4}{3}}$

For the Interval $1\leq x\leq 8$

Length of the Curve $=\int\limits^8_1 {\sqrt{\dfrac{1}{2}+x^{\frac{4}{3}}+ \dfrac{1}{16}x^{-\frac{4}{3}} } } \, dx\\$

Using T1-Calculator

$=\sqrt\frac{387}{20}$

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4 years ago

Kinda left explainitory but I need help with finding the base

almond37 [142]

Answer:

6.4 cm

Step-by-step explanation:

Area of triangle = 17.28 cm²

$\frac{1}{2}*base *altitude = 17.28\\\\\frac{1}{2}*base*5.4=17.28\\\\base = 17.28*\frac{2}{5.4}\\\\base= 3.2*2\\\\base = 6.4 cm$

5 0

3 years ago