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lana [24]
3 years ago
5

Find BD. NO LINKS ALLOWED PLEASE.​

Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
3 0

Answer:

Step-by-step explanation:

You have an angle bisector in AD. That means the sides are in proportion to to BD and DC

It's much easier just to look at the proportion.

AB / BD = AC/DC

18 / (3x - 3) = 15/(x + 5)              Cross multiply

18*(x + 5) = 15 (3x - 3)                Remove the brackets

18x + 90 = 45x - 45                  Switch the sides.

45x - 45 = 18x + 90                  Subtract 18x from both sides

<u>-18x           -18x</u>

27x - 45 = 90                           Add 45 to both sides

<u>       +45    45</u>

27x = 135

x = 5

But that's not the answer (even though it is correct). You want BD

BD = 3x - 3

BD = 3*5 - 3

BD = 15 - 3

BD = 12

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Elan Coil [88]

Answer:

x = 11

y = 2

n = 4

Step-by-step explanation:

Three equations

Look for x

Look for y

Look for n

__________________

Note that all of these are questions can be answered through isolating the variable.

Let's start with x :

Get x alone :

2(x + 5) = 3x + 1

Distribute :

(2(x) + 2(5))

2x + 10 = 3x - 1

Add 1 to both sides of the equation :

2x + 11 = 3x

Subtract 2x from both sides :

11 = x

x = 11

Next is y :

Isolate y :

3y - 4 = 6 - 2y

Add 4 to both sides :

3y = 10 - 2y

Add 2y to both sides :

5y = 10

Divide 5 from both sides to get y by itself :

y = 2

Lastly is n :

Isolate n :

3(n + 2) = 9(6 - n)

Distribute :

(3(n) + 3(2)) = (9(6) - 9(n))

3n + 6 = 54 - 9n

Subtract 54 from both sides :

3n - 48 = -9n

Subtract 3n from both sides :

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8 0
3 years ago
PLEASE HELP! 100 POINTS!!+ BRAINLIEST!!
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<em>Height of the pole (DC) is 57.2709m</em>

Step-by-step explanation:

Here, Wire DA and Wire DB supports a pole.

Given that Angle, A=54 , B= 72.

Also, AB = 23m

Now, Taking triangle BCD and Using basic trigonometry

Height of pole H = DC

TanB = \frac{DC}{BC}

BC= \frac{DC}{TanB}

Now, Taking triangle ACD and Using basic trigonometry

TanA = \frac{DC}{AC}

AC= \frac{DC}{TanA}

From figure, we know that

AC = AB + BC

AC - BC = AB = 23

Replacing values of AC and BC

\frac{DC}{TanA} - \frac{DC}{TanB}=23\\DC(\frac{1}{TanA}-\frac{1}{TanB})=23

Now, TanB= Tan72 =3.0776 and TanA = Tan54=1.3763

DC (\frac{1}{1.3763} - \frac{1}{3.0776})_= 23

DC ( 0.7265-0.3249)= 23

DC ( 0.4016 )= 23

DC = 57.2709

Thus, Height of thepole is 57.2709m

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3 years ago
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