Select all of the values of

Need help its sector area

Paladinen [302]

Area of sector

$= \frac{30}{360} \times \pi \times {(radius)}^{2}$

$= \frac{30}{360} \times \ \frac{22}{7} \times {(12)}^{2}$

$= \frac{30}{360} \times \ \frac{22}{7} \times 12 \times 12$

so the area = 37.71 square metre

8 0

2 years ago

The box which measures 70cm X 36cm X 12cm is to be covered by a canvas. How many meters of canvas of width 80cm would be require

grigory [225]

Answer:

142.2 meters.

Step-by-step explanation:

We have been given that a box measures 70 cm X 36 cm X 12 cm is to be covered by a canvas.

Let us find total surface area of box using surface area formula of cuboid.

$\text{Total surface area of cuboid}=2(lb+bh+hl)$ , where,

$l$ = Length of cuboid,

$b$ = Breadth of cuboid,

$w$ = Width of cuboid.

$\text{Total surface area of box}=2(70\cdot36+36\cdot 12+12\cdot 70)$

$\text{Total surface area of box}=2(2520+432+840)$

$\text{Total surface area of box}=2(3792)$

$\text{Total surface area of box}=7584$

Therefore, the total surface area of box will be 7584 square cm.

To find the length of canvas that will cover 150 boxes, we will divide total surface area of 150 such boxes by width of canvass as total surface area of canvas will also be the same.

$\text{Width of canvas* Length of canvass}=\text{Total surface area of 150 boxes}$

$80\text{ cm}\times\text{ Length of canvass}=150\times 7584\text{cm}^2$

$\text{ Length of canvass}=\frac{150\times 7584\text{ cm}^2}{80\text{ cm}}$

$\text{ Length of canvass}=\frac{1137600\text{ cm}^2}{80\text{ cm}}$

$\text{ Length of canvass}=14220\text{ cm}$

Let us convert the length of canvas into meters by dividing 14220 by 100 as 1 meter equals to 100 cm.

$\text{ Length of canvass}=\frac{14220\text{ cm}}{100\frac{cm}{m}}$

$\text{ Length of canvass}=\frac{14220\text{ cm}}{100}\times\frac{m}{cm}$

$\text{ Length of canvass}=142.20\text{ m}$

Therefore, 142.2 meters of canvas of width 80 cm required to cover 150 such boxes.

5 0

3 years ago

A portion of a roller coaster track is shown in the figure above. the roller coaster track is shown at ground level at point S a

eimsori [14]

Answer:

Step-by-step explanation:

This is classic right triangle trig. The height of the hill is 78.4 which serves as the side opposite the reference angle of 23 degrees. The side we are looking for is the hypotenuse of that triangle. The trig ratio that relates the side opposite a reference angle to the hypotenuse of the right triangle is the sin ratio. Setting it up using our values:

$sin(23)=\frac{78.4}{x}$ , where x is the unknown length of the hypotenuse. Solving for x: