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coldgirl [10]
3 years ago
6

There are 3 different cheeses at the deli. Yasuko buys Three-fourths of a pound of each. There are also 4 different meats. She b

uys One-half of a pound of each. How much total meat and cheese did Yasuko buy at the deli? One-fourth pounds 2 and one-fourth pounds 4 and one-fourth pounds 4 and one-half pounds
Mathematics
2 answers:
Nimfa-mama [501]3 years ago
6 0

Answer:

C

Step-by-step explanation:

Took the test

Helen [10]3 years ago
5 0

Question :

There are 3 different cheeses at the deli. Yasuko buys Three-fourths of a pound of each. There are also 4 different meats. She buys One-half of a pound of each. How much total meat and cheese did Yasuko buy at the deli? a) One-fourth pounds

b) 2 and one-fourth pounds

c) 4 and one-fourth pounds

d) 4 and one-half pounds

Answer:

c) 4 and one-fourth pounds

Step-by-step explanation:

From the question:

There are 3 different cheeses at the deli. Yasuko buys Three-fourths of a pound of each.

Total pounds of cheese = 3 × (3/4)

= 9/4 pounds of cheese

There are also 4 different meats. She buys One-half of a pound of each.

Total pounds of meats she bought = 4 × (1/2)

= 4/2 pounds of meat

The total pounds of total meat and cheese did Yasuko bought at the deli =

= 9/4 pounds of cheese + 4/2 pounds of meat

L.C.M = 4

= 9 × 1 + 4 × 2/4

= 9 + 8/4

= 17/4

= 4 1/4 pounds

In words is 4 and one-fourth pounds

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Which two equations are true?(2×10−4)+(1.5×10−4)=3.5×10−4(3×10−5)+(2.2×10−5)=6.6×10−10 (6.3×10−1)−(2.1×10−1)=3×10−1(5.4×103)−(2.
tiny-mole [99]

let me edit your question as:

Which two equations are true?

<u>Eq1:</u>

(2×10−4)+(1.5×10−4)=3.5×10−4(3×10−5)+(2.2×10−5)

<u>Eq2:</u>

6.6×10−10(6.3×10−1)−(2.1×10−1)=3×10−1(5.4×103)−(2.7×103)

<u>Eq3:</u>

2.7×103(7.5×106)−(2.5×106)=5×100

Answer:

No one is true

Step-by-step explanation:

let's check each equation, if the values on both sides (left and right side) are equal then the equation is true otherwise false.

Using PEMDAS rule we are simplifying the equations as;

<u>Eq1:</u>

(2*10-4)+(1.5*10-4)=3.5*10-4(3*10-5)+(2.2*10-5)\\(16)+(11)=35-4(25)+(17)\\27=35-100+17\\27=-48\\

<u>Eq2:</u>

<u></u>6.6*10-10(6.3*10-1)-(2.1*10-1)=3*10-1(5.4*103)-(2.7*103)\\66-10(62)-(20)=30-1(556.2)-278.1\\66-620-20=30-556.2-278.1\\-574=-804.1<u></u>

<u>Eq3:</u>

2.7*103(7.5*106)-(2.5*106)=5*100\\221089.5-265=500\\220824.5=500\\

<u>we observed that none of the equation has two same values on both sides thus none of the three equations is true.</u>

<u>Also, no value of Eq1, Eq2 or Eq3 are same thus none of the equation is true</u>

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