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2 years ago

I’ve been stuck on this for 3 days today is the last day please help me guys

Mathematics

1 answer:

OleMash [197]2 years ago

7 0

y = x^2 - 2x - 3

Factored Form: y = (x - 3)(x + 1)

X-Intercepts: (3, 0) and (-1, 0)

Axis of Symmetry: x = 1

Vertex: (1, -4)

Domain: All Real Numbers (or negative infinity to infinity)

Range: y > -4

Hope this helps!

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HELP ASAP PLEASE!!!! <br> EXTRA POINTS!!

uysha [10]

The answers are A, B, and D because to find the percent, you would have to multiply the percent by the number you're trying to get out of. There are different but correct ways written in A, B, and D.

8 0

3 years ago

I need help finding m<1 please :)

Inessa [10]

Answer

c,116°

Step-by-step explanation:

i don't know how to draw a diagram?

Join ends of chord with the center making angles ∠2,∠3 and angle at the center.

angle at the center=128°

∠1=∠2+90°

∠2=∠3

∠2+∠3+128=180

∠2+∠2+128=180

2∠2=180-128=52

∠2=52/2=26

∠1=26+90=116°

sorry i can't explain properly without picure.

5 0

3 years ago

Suppose there is a pile of quarters, dimes, and pennies with a total value of $1.08

WINSTONCH [101]

Answer:

if 1 quarter = $ 0.25

1 dime = $ 0.10

1 penny = $ 0.01

so to make the total of $1.08 and its is also required to calculate the number of each coins present without being able to make change for a dollar

therefore we say;

1 Quarter + 8 dimes + 3 penny

: ( 1 × 0.25 ) + ( 8 × 0.10 ) + ( 3 × 0.01 )

: 0.25 + 0.80 + 0.03 = $ 1.08

Now if you have a 4 Quarters, you have change for $1.

If you have 5 dimes, you have change for 2 Quarters.

If you have nickel; one of those can combine with 2 dimes to have a change for a Quarter.

If you have 5 pennies, you have enough change for 1 nickel

Therefore

(4-1)×0.25 + (5-1)×0.1 + (0×0.05) + (5-1)×0.01 = x

(3 × 0.25) + ( 4 × 0.1) + 0 + ( 4 × 0.01) = x

x = 0.75 + 0.4 + 0.04

x = $ 1.19

PROVED

6 0

3 years ago

If y varies directly as x, find the constant of variation if y= 34 when x= 2

bearhunter [10]

The answer is C

y=kx. where k is a constant
sub y=34,x=2
2k=34
k=17

7 0

3 years ago

Given that WA = 5x – 8 and WC = 3x + 2, find WB. A. WB = 5 B. WB = 8 C. WB = 10 D. WB = 17

rodikova [14]

The rest of the question is the attached figure.
============================================
Δ AYW a right triangle at Y ⇒⇒⇒ ∴ WA² = AY² + YW²
And AY = YB ⇒⇒⇒ ∴ WA² = YB² + YW² → (1)
Δ BYW a right triangle at Y ⇒⇒⇒ ∴ WB² = BY² + YW² → (2)
From (1) , (2) ⇒⇒⇒ ∴ WA = WB →→ (3)
Δ CXW a right triangle at Y ⇒⇒⇒ ∴ WC² = CX² + XW²
And CX = XB ⇒⇒⇒ ∴ WC² = XB² + XW² → (4)
Δ BXW a right triangle at Y ⇒⇒⇒ ∴ WB² = XB² + XW² → (5)
From (4) , (5) ⇒⇒⇒ ∴ WC = WB →→ (6)
From (3) , (6)
WA = WB = WC
given ⇒⇒⇒ WA = 5x – 8 and WC = 3x + 2
∴ <span> 5x – 8 = 3x + 2</span>
Solve for x ⇒⇒⇒ ∴ x = 5
∴ WB = WA = WC = 3*5 + 2 = 17

The correct answer is option D. WB = 17

7 0

3 years ago

Read 2 more answers