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RSB [31]
3 years ago
10

The end points of line segment PQ are P(1, 3), and Q(7, 7). What is the midpoint of line segement PQ?

Mathematics
1 answer:
dangina [55]3 years ago
8 0

Answer:

D) (4, 5)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Coordinates (x, y)
  • Midpoint Formula: \displaystyle (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

Step-by-step explanation:

<u>Step 1: Define</u>

Point P(1, 3)

Point Q(7, 7)

<u>Step 2: Identify</u>

P(1, 3) → x₁ = 1, y₁ = 3

Q(7, 7) → x₂ = 7, y₂ = 7

<u />

<u>Step 3: Find Midpoint</u>

Simply plug in your coordinates into the midpoint formula to find midpoint

  1. Substitute in points [Midpoint Formula]:                                                       \displaystyle (\frac{1+7}{2},\frac{3+7}{2})
  2. [Midpoint] Add:                                                                                               \displaystyle (\frac{8}{2},\frac{10}{2})
  3. [Midpoint] Divide:                                                                                            \displaystyle (4,5)
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Anna bought p packages of paper plates at Party City that cost $4 per package and c packages of cups that cost $3 per package. S
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Calculate the value of x in the equation 2x - 15 =5 - 3×
pshichka [43]

\bold{2x - 15 = 5 - 3x} \\  \bold{2x + 3x = 15  +  5} \\  \bold{5x =20 } \\  \bold{x =  \cancel{ \frac {20}{5} }} \\  \bold{x = 4}

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1 year ago
Read 2 more answers
The means and mean absolute deviations of Sidney’s and Phil’s grades are shown in the table below which expression represents th
Shalnov [3]

The ratio of the difference of the two means to Sidney’s mean absolute deviation is; 4/3.28

<h3>How to find the Mean Absolute Deviation?</h3>

From the given table, we see that;

Mean grade of Sidney = 82

Mean grade of Phil = 78.

Mean absolute deviation of Sidney = 3.28

Mean absolute deviation of Phil = 3.96.

The difference between the two means of Sidney and Phil = 82 - 78 = 4.

Thus, the ratio of the difference of the two means to Sidney’s mean absolute deviation is; 4/3.28

Complete Question is;

The means and mean absolute deviations of Sidney’s and Phil’s grades are shown in the table below. Means and Mean Absolute Deviations of Sidney’s and Phil’s Grades Sidney Phil Mean 82 78 Mean Absolute Deviation 3.28 3.96 Which expression represents the ratio of the difference of the two means to Sidney’s mean absolute deviation?

Read more about Mean Absolute Deviation at; brainly.com/question/447169

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2 years ago
What is the volume of a cube whose surface area is 294 in2?
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Answer:

V=343in³

Step-by-step explanation:

A=6a2

V=a

3V=6A3/2

36=6·2943/2

36=343in³

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3 years ago
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