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elixir [45]
3 years ago
6

Một xưởng dệt thảm được giao làm một số thảm trong 30 ngày. Thực tế xưởng dệt đã tăng năng xuất lên 25% nên sau 25ngay không nhữ

ng đã làm xong số thảm mà còn làm thêm được 20 chiếc nữa. Tính số lượng thảm mà xưởng đã dệt trong 25 ngày
Mathematics
1 answer:
grigory [225]3 years ago
8 0

Gọi số tấm thảm xưởng dệt dệt theo dự định là x ( tấm, x >0 )

⇒ số tấm thảm xưởng dệt dệt trong 1 ngày theo dự định x/30 (tấm)

xưởng dệt dệt đc số tấm thảm trong thực tế là x/20 (tấm)

⇒số tấm thảm xưởng dệt dệt trong 1 ngày thực tế là x+20/25 (tấm)

Vì năng suất tăng 25% nên số tấm thảm dệt được trong 1 ngày thực tế sẽ bằng 125% số tấm thảm dệt đc trong 1 ngày theo dự định nên ta có PT : x+20/25=125% * x/30

me lười làm khúc dưới quá nên tự xử nha.

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Prove that step by step ​
Elza [17]

Answer:

In ΔECB ,

∠ECD = ∠EBC + ∠BEC (∵ Exterior Angle Property of a triangle)

⇒ ∠BEC = ∠ECD - ∠EBC  ................. eqn.1

In ΔABC ,

∠ACD = ∠BAC + ∠ABC (∵ Exterior Angle Property of a triangle )

⇒ 2∠ECD = ∠BAC + 2∠EBC

⇒ ∠BAC = 2∠ECD - 2∠EBC = 2(∠ECD - ∠EBC)

( Putting eqn.1 here )

⇒ ∠BAC = 2∠BEC  (∵∠BEC = ∠ECD - ∠EBC)

3 0
3 years ago
for simplicity, let X=M G = 1 I = 2 if you like decimals C = 3 + 0.75Y or if you prefer fractions C = 3 + 3/4Y the simple multip
serg [7]

Answer:

the simple multiplier is equal to 4

Step-by-step explanation:

In an economic model,

Y=  C + I + G + (X - M)

the average expenditure Y must be equal  to the totality of the output

If C = 3 + 0.75Y

where;

marginal propensity to consume MPC = 0.75

Then,

Y = 3 + 0.75Y + 2 + 1

Y = 6+0.75 Y

Y - 0.75 Y = 6

0.25 Y = 6

Y = 6/0.25

Y = 24

However,  the simple multiplier can be expressed as:

=\dfrac{1}{1 - MPC}

=\dfrac{1}{1 - 0.75}

=\dfrac{1}{0.25}

= 4

7 0
4 years ago
Gold’s gym charges $30 membership fee plus $3 for each workout, while Titletown charges $40 membership fee plus $1 for each work
ollegr [7]

Answer:

5 workouts should be performed to equalize the costs between both gyms.

Step-by-step explanation:

Given that Gold’s gym charges $ 30 membership fee plus $ 3 for each workout, while Titletown charges $ 40 membership fee plus $ 1 for each workout, to determine how many workouts does a person have to do until the total costs are equal, the following calculation must be performed:

Gold's Gym: y = 30 + 3x

Titletown Fitness: y = 40 + x

Gold's Gym: y = 30 + 3x2 = 36

Titletown Fitness: y = 40 + 2 = 42

Gold's Gym: y = 30 + 3x3 = 39

Titletown Fitness: y = 40 + 3 = 43

Gold's Gym: y = 30 + 3x4 = 42

Titletown Fitness: y = 40 + 4 = 44

Gold's Gym: y = 30 + 3x5 = 45

Titletown Fitness: y = 40 + 5 = 45

Thus, 5 workouts should be performed to equalize the costs between both gyms.

3 0
3 years ago
If Dominik completes a project by himself, it will take him 8 hours. Working with Katarina, it will take them 5 hours.
Andreas93 [3]
I think the answer is D, I've been told it's D by many people.
7 0
3 years ago
Read 2 more answers
Rewa Delta Union Rugby CEO has become concerned about the slow pace of the rugby games played in the current union rugby, fearin
ozzi

Answer:

We conclude that the mean duration of 15-sided union rugby games has decreased after the meeting.

Step-by-step explanation:

We are given that Before the meeting, the mean duration of the 15-sided rugby game time was 3 hours, 5 minutes, that is, 185 minutes.

A random sample of 36 of the 15-sided rugby games after the meeting showed a mean of 179 minutes with a standard deviation of 12 minutes.

Let \mu = <em><u>mean duration of 15-sided union rugby games after the meeting.</u></em>

So, Null Hypothesis, H_0 : \mu \geq 185 minutes      {means that the mean duration of 15-sided union rugby games has increased or remained same after the meeting}

Alternate Hypothesis, H_A : \mu < 185 minutes     {means that the mean duration of 15-sided union rugby games has decreased after the meeting}

The test statistics that would be used here <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

                            T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean duration of 15-sided union rugby games = 179 min

            s = sample standard deviation = 12 minutes

            n = sample of 15-sided rugby games = 36

So, <u><em>the test statistics</em></u>  =  \frac{179-185}{\frac{12}{\sqrt{36} } }  ~ t_3_5

                                       =  -3

The value of t test statistics is -3.

<u>Now, at 1% significance level the t table gives critical value of -2.437 at 35 degree of freedom for left-tailed test.</u>

Since our test statistic is less than the critical value of t as -3 < -2.437, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that the mean duration of 15-sided union rugby games has decreased after the meeting.

6 0
4 years ago
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