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AlekseyPX
3 years ago
10

3. What is the sum of 1/9, 2/3, and 5/18?А. 19/18b. 4/15C. 12/9D. 8/30​

Mathematics
1 answer:
4vir4ik [10]3 years ago
4 0

Answer:

A,19/18

Step-by-step explanation:

I don't know exactly how to explain it...

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Please help fast i will give you the most Brainly <br><br><br> what would n = 3(n+7)=48
neonofarm [45]

Answer:

n = 9

Step-by-step explanation:

3(n+7)=48

distribute

3n +21 = 48

subtract 21 from each side

3n = 48-21

3n = 27

divide by 3

3n/3 = 27/3

n = 9

5 0
3 years ago
The age of father is 4nyears.If the age of his daughter is(2n-9)years.find their total age.​
8_murik_8 [283]

Answer:

4n+(2n-9)

4n+2n-9

6n-9 =the total age

6n=9

divide by 6 both sides.

n=9/6

n=1.5 years.

substitute the value of n in the age of the father and the daughter.

Age of father=4×1.5

6years.

Age of Daughter = (2×1.5)-9

3-9

=-6 years

Total age

6-6=0

4 0
3 years ago
What is function and how is it related to domain and range?​
const2013 [10]

Answer:

Function- a relationship or expression involving one or more variables.

A domain refers to the set of possible input values.

The range is the set of possible output values.

Step-by-step explanation:

4 0
3 years ago
EX 6.1 How many iterations will the following for loops execute? for (int i = 0; i &lt; 20; i+ +) { } for (int i = 1; i &lt;= 20
Romashka-Z-Leto [24]

Answer:

20, 20, 15, 20, 10, and 5 iterations respectively

Step-by-step explanation:

The loop "for (int i = 0; i < 20; i+ +)" starts at i=0 and increases the counter i by 1 at the end of each iteration. The counter must be less than 20, so the values of i in the loop are 0,1,2,3,...,19. These are 20 values, and thus the code iterated 20 times.

The loop "for (int i = 0; i < 20; i+ +)" starts at i=1 and increases the counter i by 1 at the end of each iteration. The counter can't exceed 20, so the values of i in the loop are 1,2,3,4,...,20. These are 20 values, and thus the code iterated 20 times.

Similarly, in "for (int i = 5; i < 20; i+ +)" i takes the 15 values are 5,6,7,...,19. Hence, the code iterated 15 times.

The loop "for (int i = 20; i > 0; i- -)" starts at i=20 and decreases the counter i by 1 at the end of each iteration, so the values of i in the loop are 20,19,18,...,1. These are 20 values, then we have 20 iterations.

The loop "for (int i = 1; i < 20; i = i + 2)" starts at i=1 and increases the counter i by 2 at the end of each iteration. The values of i in the loop are 1,3,5,7,...,19. These are 10 values, and thus the code iterated 10 times.

The loop "for (int i = 0; i < 20; i+ +)" starts at i=1 and multiplies the counter i by 2 at the end of each iteration, so the values of i in the loop are 1,2,4,8,16. Then we have 5 iterations.

6 0
3 years ago
PLS HELP, WILL REWARD BRAINLIEST !!
Mrac [35]
B is the answer to this
4 0
3 years ago
Read 2 more answers
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