C
Step-by-step explanation:
Let the number of red, black, green and blue balls be R, B, G, U respectively.
B=R (There are as many black balls as red balls)
G+R=10 so G=10-R (Green balls and red balls should add up to 10)
R+10=U (There should be 10 more blue balls than red balls)
The minimal number of balls is 2, 304 so we have the following inequality:
R+B+G+U≥ 2,304
R+(R)+(10-R)+ (R+10)≥2,304
4R≥2,304
R≥2,304/4=576 so R=576
Answer: 576
Plug 7/50 into your calculator to get 0.14. The answer is C.
Rewrite the original equation as:
Log(4x^2) - log(3yz)
Rewrite log(4x^2) as log(4) + log(x^2)
Rewrite log(4) as 2log(2)
Rewrite log(x^2) as 2log(x)
Separate log(3yz) into 3 logs: log(3), log(y) and log(z)
Now combine them to get:
2log(2) + 2log(x) - log(3) - log(y) - log(z)
