<em>Note:</em><em> You missed to add some of the details of the question.
</em>
<em>Hence, I am solving your concept based on an assumed graph which I have attached. It would anyways clear your concept.</em>
<em></em>
Answer:
Please check the explanation.
Step-by-step explanation:
Given the right angled-triangle ABC as shown in the attached diagram
From the triangle:
Ф= ∠C = 30°
AB = 6 units
BC = y
tan Ф = opp ÷ adjacent
The opposite of ∠C = 30° is the length '6'.
The adjacent of ∠C = 30° is the length 'y'.
As Ф= ∠C = 30°
so
tan Ф = opp ÷ adjacent
tan 30 = 5 ÷ y
1 ÷ √3 = 5 ÷ y
y = 8.7 units
Therefore, the length of the unknown side length 'y' is 8.7 units.
Answer:
Answer:
m=−7
Step-by-step explanation:
Let's solve your equation step-by-step.
2981
35
=
−11
7
(8m+
9
5
)
Step 1: Simplify both sides of the equation.
2981
35
=
−11
7
(8m+
9
5
)
2981
35
=(
−11
7
)(8m)+(
−11
7
)(
9
5
)(Distribute)
2981
35
=
−88
7
m+
−99
35
Step 2: Flip the equation.
−88
7
m+
−99
35
=
2981
35
Step 3: Add 99/35 to both sides.
−88
7
m+
−99
35
+
99
35
=
2981
35
+
99
35
−88
7
m=88
Step 4: Multiply both sides by 7/(-88).
(
7
−88
)*(
−88
7
m)=(
7
−88
)*(88)
m=−7
Answer:
m=−7
Answer:
option: B is correct
A reflection across line n followed by a 270° rotation about point P.
Step-by-step explanation:
Clearly from the figure we could see that the graph is first reflected across the given line n such that we obtain the figure R'S'T'V'U' and then it is rotated 270° across the point P so that we obtain the figure R"S"T"U"V".
Hence, option B is correct.
( A reflection across line n followed by a 270° rotation about point P )
-8 you divide and since there is a negative you add a negative
Given parameters:
Length of earring hook = 1.5cm
Length of given wire = 45cm
Dimension of the triangle = 3.2cm, 3.2cm and 2.1cm
Unknown:
Number of earrings that can be made from the wire = ?
To solve this problem, we need to calculate the total length of the earring we want to make.
Total earring length = Perimeter of earring + length of earring hook
= 3.2 + 3.2 + 2.1 + 1.5
= 10cm
Now the length of the wire is 45cm,
Number of earrings = 
= 4.5 earrings
But this is not reasonable, therefore, we can only forge 4 complete earrings from the given length with 5cm of wire remaining.
The number of earrings that can be made is 4.
