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marishachu [46]
3 years ago
11

Are the following equations balanced or unbalanced?

Chemistry
1 answer:
Butoxors [25]3 years ago
5 0
1. balanced
2. balanced
3. unbalanced
4. balanced
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2. Heliox is a mixture of gases and is used in medicine to help
yaroslaw [1]

Answer:

people with breathing problems such as severe asthma.

Explanation:

Heliox is a medical treatment for patients with difficulty breathing. The mixture generates less resistance than atmospheric air when passing through the airways of the lungs, and thus requires less effort by a patient to breathe in and out of the lungs.

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Which of the following is a result of increasing the temperature of a system that includes a reaction in the forward direction t
kogti [31]

Answer:

I believe the answer your looking for is out of A or B

Explanation:

Option B because if the heat increases its essentially causing the concentration to increase by replacing the weak bonds with stronger ones

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Match each element of poetry with the correct expert
zzz [600]

Answer:

is there a picture of the problem

Explanation:

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3 years ago
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Is migration a long term consequence for competitive exclusion
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long term consequence, not many can come back from it


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3 years ago
The electron in a hydrogen atom, originally in level n = 8, undergoes a transition to a lower level by emitting a photon of wave
timofeeve [1]

Explanation:

It is given that,

The electron in a hydrogen atom, originally in level n = 8, undergoes a transition to a lower level by emitting a photon of wavelength 3745 nm. It means that,

n_i=8

\lambda=3745\ nm

The amount of energy change during the transition is given by :

\Delta E=R_H[\dfrac{1}{n_f^2}-\dfrac{1}{n_i^2}]

And

\dfrac{hc}{\lambda}=R_H[\dfrac{1}{n_f^2}-\dfrac{1}{n_i^2}]

Plugging all the values we get :

\dfrac{6.63\times 10^{-34}\times 3\times 10^8}{3745\times 10^{-9}}=2.179\times 10^{-18}[\dfrac{1}{n_f^2}-\dfrac{1}{8^2}]\\\\\dfrac{5.31\times 10^{-20}}{2.179\times 10^{-18}}=[\dfrac{1}{n_f^2}-\dfrac{1}{8^2}]\\\\0.0243=[\dfrac{1}{n_f^2}-\dfrac{1}{64}]\\\\0.0243+\dfrac{1}{64}=\dfrac{1}{n_f^2}\\\\0.039925=\dfrac{1}{n_f^2}\\\\n_f^2=25\\\\n_f=5

So, the final level of the electron is 5.

4 0
3 years ago
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