Hey there,
Smelting's main use is to produce a base metal from its ore
Hope this helps :))
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To answer the question above, substitute the given values to the given equation,
Q(t) = Q x e^-kt
12 grams = (36 grams) x e^(-0.00011)(t)
Solving for t gives t = 9,987.38 years or approximately equal to 9,990 years. Thus, the answer is letter C.
<span> are composed of the fragments, or CLASTS. If PRE-existing </span>minerals<span> and rock. A </span>clast<span> is a fragment of </span>geological detritus,<span>chunks and smaller grains of rock broken off other rocks by </span>physical weathering.[2]<span> Geologists use the term CLASTIC </span><span>with reference to </span>sedimentary rocks<span> as well as to particles in </span>sediment transport<span> whether in </span>suspension<span> or as </span>bed load<span>, and in </span>sediment<span> deposits.</span>
<span>We look at the end of the day:
n(HNO3) added = 0.500*17.0/1000 = 0.00850 mol
n(NH3) = 0.200*75.0/1000 - 0.00850 = 0.00650 mol
[NH3] left = 0.00650*1000/(17.0+75.0) = 0.070652
M [OH-] = Kb * [NH3] = 0.070652*1.8*10^(-5) = 1.27174 x 10^(-6)
pOH = -log[OH-] ≈ 5.8956 pH = 14 - pOH ≈ 8.10</span>
Answer is: 9,7 L is needed to store helium gas.
n(He) = 0,80 mol.
p(He) = 204,6 kPa.
T = 300 K.
R = 8,314 J/K·mol; universal gas constant.
Use ideal law eqaution: p·V = n·R·T.
V = n·R·T / p.
V(He) = 0,80 mol · 8,314 J/K·mol · 300 K ÷ 204,6 kPa.
V(He) = 9,75 L.
