Solution..
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Let's calculate the mass of CO₂.
We have (12+(16*2))
= 12+32
=44gmol¯¹..
a. What is the percent by mass of carbon?
Mass of carbon /mass of CO₂ × 100%
12/44 × 100%
=27.3%...
b. What is the percent by mass of oxygen?
Mass of oxygen/mass of CO₂ × 100%
(2×16)/44 × 100%
32/44 × 100%
=72.7%....
To check.. You'll add this two percentage compositions together and see of it gives 100%... If it does then we're good...
27.3%+72.7% = 100%.... Checked..
Hope this helped....?
B aluminum is more reactive them sulfur!!
usibility is the correct once...........................................
