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777dan777 [17]
3 years ago
10

Question 7

Chemistry
1 answer:
Zigmanuir [339]3 years ago
8 0

The correct answer to the question is:

<h3>1 O atom / 2 H atom</h3>

Sucrose is an organic compound with a molecular formula of C₁₂H₂₂O₁₁

With the molecular formula of sucrose, we can obtain the relationship of oxygen and hydrogen in the compound. This can be obtained as follow:

Sucrose => C₁₂H₂₂O₁₁

Hydrogen atom = 22

Oxygen atom = 11

<h3>Oxygen to Hydrogen =? </h3>

Oxygen to Hydrogen = 11 / 22

<h3>Oxygen to Hydrogen = 1/2</h3>

Therefore, the simple unit factor that relates the number of hydrogens in sucrose to the number of oxygens is:

1 O atom / 2 H atom

Learn more: brainly.com/question/7281916

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Answer:

ΔH°rxn = 54.08 kJ

Explanation:

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According to Hess's law, the enthalpy change in a chemical reaction is the same whether the reaction takes place in one or in several steps. That means that we can find the enthalpy of a reaction by adding the corresponding steps and adding their enthalpies. According to Lavoisier-Laplace's law, if we reverse a reaction, we also have to reverse the sign of its enthalpy.

Let's reverse equation a) and add it to equation b).

-a) Cl(g) + 2 O₂(g) ⇄ ClO(g) + O₃(g)                    ΔH°rxn = 29.90 kJ

b) 2 O₃(g) ⇄ 3 O₂(g)                                            ΔH°rxn = 24.18 kJ

-------------------------------------------------------------------------------------------------

Cl(g) + 2 O₂(g) + 2 O₃(g) ⇄ ClO(g) + O₃(g) + 3 O₂(g)

Cl(g) + O₃(g) ⇄ ClO(g) +O₂(g)

ΔH°rxn = 29.90 kJ + 24.18 kJ = 54.08 kJ

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