Let

. Then

. By convention, every non-zero integer

divides 0, so

.
Suppose this relation holds for

, i.e.

. We then hope to show it must also hold for

.
You have

We assumed that

, and it's clear that

because

is a multiple of 3. This means the remainder upon divides

must be 0, and therefore the relation holds for

. This proves the statement.
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<span>C) The expected value is - $2,000, so the company should not proceed with the project.</span>
Answer:
-7
Step-by-step explanation:
Answer:
100
Step-by-step explanation:
Answer:

Step-by-step explanation:

Convert the given fractions into like fractions.
To do so, Take the L.C.M ( Least Common Multiple ) of 3 and 4.
To find out the L.C.M of given numbers,
First of all, find the prime factors of each numbers.
3 = 3 × 1
4 = 2 × 2 × 1
Take out the common prime factor i.e 1
Also take out the other remaining prime factors i.e 2 , 2 and 3
Now, multiply those all prime factors and obtain L.C.M
= 1 × 2 × 2 × 3 = 12
L.C.M of 3 and 4 = 12


Add the numbers : 20 and 21

Convert the improper fraction into mixed fraction

Remember : While performing the addition or subtraction of unlike fractions, you have to express the given fractions into equivalent fractions of common denominator and add or subtract as we do with like fractions. Thus , obtained fractions should be reduced into lowest terms if there are any common on numerator and denominator. But in case of improper fraction, it needs to be deduced on mixed fraction.
Hope I helped!
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~ TheAnimeGirl