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3 years ago

What are the factors of58

Mathematics

1 answer:

liubo4ka [24]3 years ago

8 0

<span>1,2, 29,and 58 are the factors of 58.</span>

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Erin calculated the average speed of her most recent run to be 120/16 miles per hour how is this friction expressed as a decimal

Contact [7]

Answer:

$\dfrac{15}{2}$

Step-by-step explanation:

The average speed of the Erin is 120/16 mph

Here,

Numerator = 120

Denominator = 16

mph = miles per hour

We need to find an expression expressed as a decimal.

So,

$\dfrac{120}{16}=\dfrac{2\times 3\times 2\times 2\times 5}{2\times 2\times 2\times 2}\\\\=\dfrac{15}{2}$

So, the final answer is $\dfrac{15}{2}$ .

4 0

3 years ago

4h+7=4h-3 i think i have it but im not sure 100% so i need hlp

SSSSS [86.1K]

<u>4h + 7 = 4h - 3</u>

Subtract 4h from each side: 7 = -3

There is no value of ' h ' that can make this a true statement,
so the equation has no solution.

5 0

3 years ago

Read 2 more answers

Find the prime factorization 360

frez [133]

Answer:

1, 2, 3, 4, 5, 6, 8, 9, 10, 12, 15, 18, 20, 24, 30, 36, 40, 45, 60, 72, 90, 120, 180, 360

Step-by-step explanation:

5 0

3 years ago

Solve the following compound inequality.

Verdich [7]

The following compound? what’s the following compound

7 0

3 years ago

Standard deviation 12,16,22,23,34,44,46,47,48,64,67,73,83,89, round to nearest tenth

RideAnS [48]

Answer: 23.9

Step-by-step explanation:

1. First, you must calculate the mean, as following:

$\frac{12+16+22+23+34+44+46+47+48+64+67+73+83+89}{14}=47.71$

2. Now, you should substract the means obtained to every single number of the set and then square it. Add all of them:

$(12-47.71)^{2}+(16-47.71)^{2}+(22-47.71)^{2}+(23-47.71)^{2}+(34-47.71)^{2}+(44-47.71)^{2}+(46-47.71)^{2}+(47-47.71)^{2}+(48-47.71)^{2}+(64-47.71)^{2}+(67-47.71)^{2}+(73-47.71)^{2}+(83-47.71)^{2}+(89-47.71)^{2}=7984.86$

3. The mean of this is:

$\frac{7984.8574}{14}=570.35$

4. The square root of this result is:

$\sqrt{2.52}=23.88$

5. To the nearest tenth, the result is: 23.9

5 0

3 years ago