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Grace [21]
2 years ago
5

Is a 39 Celsius body temperature higher than normal 98 Fahrenheit?? Yes or No

Mathematics
1 answer:
Umnica [9.8K]2 years ago
5 0

Answer:

Yes.

Step-by-step explanation:

According to medical science, a body temperature considered normal (that is, below fever) in degrees Fahrenheit is 98ºF, while its equivalent in degrees Celsius is 36.6ºC. Therefore, a body temperature of 39ºC is higher than 98ºF, being equivalent to 102.2ºF.

This is verified by applying the conversion formula from Celcius to Fahrenheit:

(39 x 9/5) + 32 = X

39 x 1.8 + 32 = X

70.2 + 32 = X

102.2 = X

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A street light is at the top of a 15 ft tall pole. A woman 6 ft tall walks away from the pole with a speed of 6 ft/sec along a s
kakasveta [241]

Answer:

4 ft/sec

Step-by-step explanation:

Hope it helps

6 0
2 years ago
12. Use a trigonometric ratio to find the measure of O in the triangle below. Give your answer to the nearest degree.
larisa [96]

<u>G</u><u>iven </u><u>:</u><u>-</u>

  • A right angled triangle with two sides 10cm and 9cm .

<u>To </u><u>Find</u><u> </u><u>:</u><u>-</u>

  • The value of theta .

<u>Solution</u><u> </u><u>:</u><u>-</u>

At angle theta , 9cm side will be considered as the perpendicular and 10cm side will be hypotenuse . So , as we know that ;

\longrightarrow sin\theta =\dfrac{perpendicular}{hypotenuse}

Substituting the respective values,

\longrightarrow sin\theta =\dfrac{9cm}{10cm}

Simplify,

\longrightarrow sin\theta= 0.9

Take arcsin both sides ,

\longrightarrow \theta =sin^{-1}(0.9)

\\\longrightarrow\underline{\underline{\theta = 64.15^o }}

<u>Hence</u><u> the</u><u> required</u><u> answer</u><u> is</u><u> </u><u>6</u><u>4</u><u>.</u><u>1</u><u>5</u><u>°</u><u> </u><u>.</u><u> </u>

6 0
2 years ago
The SAT Reasoning Test (formerly called the Scholastic Aptitude Test) is perhaps the most widely used standardized test for coll
slamgirl [31]

Answer:

The score is  x  =  1884

Step-by-step explanation:

From the question we are told that

     The population mean is  \mu  = 1500

     The standard deviation is  \sigma  =  300

     

From the question we are told that the score follow a normal distribution

i.e     X  \~  \   N( 1500 , 300)

The proportion of score in the top 10% is mathematically

           P(X > x )  =  P( \frac{X -  \mu}{\sigma }  > \frac{x -  \mu}{\sigma }   ) = 0.10

Where x is the minimum score required to be in the top 10%

Now the \frac{X -  \mu}{\sigma }   =  Z (The  \ Standardized \ value \  of  \  X)

  So

            P(X > x )  =  P( Z > \frac{x -  \mu}{\sigma }   ) = 0.10

So

            P(X > x )  =  P( Z > \frac{x -  1500}{300}   ) = 0.10

So the critical value of  0.10  from the normal distribution table is  Z_{0.10} =  1.28

So

               \frac{x -  1500}{300}   = 1.28

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6 0
3 years ago
Can someone help me with this question?
Andrei [34K]

Answer:

I don’t know what 14 and 15 are but I know 16 is 6 ft

Step-by-step explanation:


3 0
3 years ago
1. Find the sum of the measures of the interior angles of a convex 11-gon.
OleMash [197]

Answer:

The measure of the sum of interior angles of a 11-gon is 1620^{o}.

Each interior angle is approximately 147.273^{o}.

Step-by-step explanation:

A convex polygon has the measure of each interior angles to be less than 180^{o}.

But,

sum of interior angles of polygon = (n - 2) x 180^{o}

where n is the number of sides of the polygon.

For a convex 11-gon, we have;

sum of angles of a 11-gon = (11 - 2) x 180^{o}

                                         = 9 x 180^{o}

                                         = 1620^{o}

Sum of angles of a 11-gon = 1620^{o}

To check: convex polygons' interior angles are less than 180^{o}.

so that,

each interior angle of 11-gon = \frac{1620}{11}

                                        = 147.273^{o}

3 0
3 years ago
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