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user100 [1]
3 years ago
6

What is the midpoint of a segment shown below?

Mathematics
2 answers:
Gekata [30.6K]3 years ago
7 0

Answer:

C. (2,0)

Step-by-step explanation:

You use this equation to solve it:

(\frac{-2+6}{2}, \frac{4+(-4)}{2})

This is basically taking the average of the points.

The answer is thus (2,0)

kipiarov [429]3 years ago
3 0

Answer:

(2,0)

Step-by-step explanation:

To find the x coordinate of the midpoint, add the x coordinates together and  divide by 2

(-2+6)/2 = 4/2 =2

To find the y coordinate of the midpoint, add the y coordinates together and  divide by 2

(4+-4)/2 = 0/2 =0

(2,0)

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Match each pair of points to the equation of the line that is parallel to the line passing through the pointsB(5,2) and C(7,-5)Y
a_sh-v [17]

we will select each points and find equation of line

option-A:

points are B(5,2) and C(7,-5)

x1=5,y1=2 , x2=7 , y2=-5

Firstly, we will find slope

m=\frac{y_2-y_1}{x_2-x_1}

we can plug values

m=\frac{-5-2}{7-5}

m=-3.5

we can use point slope form of line

y-y_1=m(x-x_1)

we can plug values

y-2=-3.5(x-5)

y=\frac{-7}{2}x+\frac{39}{2}...........Answer

option-B:

points are D(11,6) and E(5,9)

x1=11,y1=6 , x2=5 , y2=9

Firstly, we will find slope

m=\frac{y_2-y_1}{x_2-x_1}

we can plug values

m=\frac{9-6}{5-11}

m=-0.5

we can use point slope form of line

y-y_1=m(x-x_1)

we can plug values

y-6=-0.5(x-11)

y=\frac{-1}{2}x+\frac{23}{2}...........Answer

option-C:

points are F(-7,12) and G(3,-8)

x1=-7,y1=12 , x2=3 , y2=-8

Firstly, we will find slope

m=\frac{y_2-y_1}{x_2-x_1}

we can plug values

m=\frac{-8-12}{3+7}

m=-2

we can use point slope form of line

y-y_1=m(x-x_1)

we can plug values

y-12=-2(x+7)

y=-2x-2...........Answer

option-D:

points are H(4,4) and I(8,9)

x1=4,y1=4 , x2=8 , y2=9

Firstly, we will find slope

m=\frac{y_2-y_1}{x_2-x_1}

we can plug values

m=\frac{9-4}{8-4}

m=1.25

we can use point slope form of line

y-y_1=m(x-x_1)

we can plug values

y-4=1.25(x-4)

y=\frac{5}{4}x-1...........Answer

option-E:

points are J(7,2) and K(-9,8)

x1=7,y1=2 , x2=-9 , y2=8

Firstly, we will find slope

m=\frac{y_2-y_1}{x_2-x_1}

we can plug values

m=\frac{8-2}{-9-7}

m=-\frac{3}{8}

we can use point slope form of line

y-y_1=m(x-x_1)

we can plug values

y-2=\frac{3}{8}(x-7)

y=\frac{3}{8}x-\frac{5}{8}...........Answer

option-F:

points are L(5,-7) and M(4,-12)

x1=5,y1=-7 , x2=4 , y2=-12

Firstly, we will find slope

m=\frac{y_2-y_1}{x_2-x_1}

we can plug values

m=\frac{-12+7}{4-5}

m=5

we can use point slope form of line

y-y_1=m(x-x_1)

we can plug values

y+7=5(x-5)

y=5x-32...........Answer



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A. place a closed circle on -4 and shade to the right. 
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1.Graph the equation y = 6x -18:
RSB [31]

Answer:

1. Given the equation: y =6x-18                        ......[1]

The intercepts of a line are the points where the line intercepts or crosses the horizontal and vertical axes.

(A)

Horizontal intercept(x) states that the point where the line crosses the x-axis and at this point y=0

Put y=0 in equation [1]

0=6x-18 or

6x=18

<h3>⇒x=3</h3>

Ordered pair of horizontal intercept(x) = (3,0)

(B)

Vertical intercept(y) states that the point where the line crosses the y-axis and at this point x=0.

Put x=0 in equation [1]

y=6\cdot 0-18 or

y=-18

<h3>⇒y=-18</h3>

Ordered pair of vertical intercept(y) = (0,-18)

You can also see the graph  of the function y =6x-18 as shown in Figure-1.

2.

Graph the equation y+2x =4

to find the horizontal intercept and vertical intercept we follow the same process as done in 1

(A)

Horizontal intercept (x) = 2

Ordered pair = (2,0)

(B)

Vertical intercept (y) = 4

Ordered pair = (0,4)

Also, you can see these in the graph as shown in the Figure-2

3.

Given: The slope(m) of a line is \frac{3}{4}

Two lines are parallel if their slopes are equal and they have different y - intercepts.

(A).

The slope of a line parallel to it is, \frac{3}{4}

(B)

The slope of the original line is  \frac{3}{4}.

A line perpendicular to another line  has a slope that is the negative reciprocal of the slope of the other line.

Therefore, slope of a line perpendicular to it is; -\frac{1}{m} = -\frac{4}{3}

4.

The graph of the equation y =4x+5 as shown in figure 3

The x-intercept of this line is \frac{-5}{4} = -1.25

And the y-intercept of this line is y =5.

5.

Graph of the equation y = -3 represents the line as shown in figure 4.

6.

Solve the equation:

6y-18x = -18

6y = 18x-18

Divide by 6 to both sides of an equation ; we get

y = 3x-3 or

y = 3(x-1)


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3 years ago
If Fred’s age now is three times what it was 12 years ago, how old is Fred 12 years ago?
Nikitich [7]

Answer:

6

Step-by-step explanation:

12+x=3x

2x=12

x=6

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