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2 years ago

Help me plis y need help with this problem !!

Chemistry

1 answer:

Maksim231197 [3]2 years ago

4 0

Answer:

a. K₃PO₄ + 3 HCl ⇒ 3 KCl + H₃PO₄

b. C₂H₆ + 3.5 O₂ ⇒ 2 CO₂ + 3 H₂O

c. KClO₃ ⇒ KCl + 1.5 O₂

Explanation:

a. Let's consider the following unbalanced equation. This is a double displacement reaction.

K₃PO₄ + HCl ⇒ KCl + H₃PO₄

We will begin balancing K atoms by multiplying KCl by 3.

K₃PO₄ + HCl ⇒ 3 KCl + H₃PO₄

Then, to balance Cl atoms, we multiply HCl by 3. This will be the balanced equation.

K₃PO₄ + 3 HCl ⇒ 3 KCl + H₃PO₄

b. Let's consider the following unbalanced equation. This is a combustion reaction.

C₂H₆ + O₂ ⇒ CO₂ + H₂O

First, we will balance C atoms by multiplying CO₂ by 2.

C₂H₆ + O₂ ⇒ 2 CO₂ + H₂O

Then, we balance H atoms by multiplying H₂O by 3.

C₂H₆ + O₂ ⇒ 2 CO₂ + 3 H₂O

Finally, we get the balanced equation multiplying O₂ by 3.5.

C₂H₆ + 3.5 O₂ ⇒ 2 CO₂ + 3 H₂O

c. Let's consider the following unbalanced equation. This is a decomposition reaction.

KClO₃ ⇒ KCl + O₂

Since K and Cl atoms are balanced, we will get the balanced equation multiplying O₂ by 1.5.

KClO₃ ⇒ KCl + 1.5 O₂

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ASAP PLEASEE

Agata [3.3K]

Seven diatomic elements are H₂, Cl₂, N₂, F₂, Br₂, I₂ and O₂.

<h3>Which are diatomic molecules?</h3>

Diatomic molecules are those molecules in which two atoms of same elements are present, and they are combined to attain the stability.

The seven diatomic molecules which are exist in the chemistry are:

Hydrogen gas (H₂)
Chlorine gas (Cl₂)
Nitrogen gas (N₂)
Fluorine gas (F₂)
Bromine gas (Br₂)
Iodine gas (I₂)
Oxygen gas (O₂)

Hence H₂, Cl₂, N₂, F₂, Br₂, I₂ and O₂ are 7 diatomic molecules.

To know more about diatomic molecules, visit the below link:
brainly.com/question/14466404

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7 0

1 year ago

A 2.5 mol sample of phosphorus pentachloride, PCl5 dissociates at 160C and 1.00atm to give 0.338 mol of phosphorus trichloride a

Readme [11.4K]

Explanation:

Moles of phosphorus pentachloride present initially = 2.5 mol

Moles of phosphorus trichloride at equilibrium = 0.338 mol

$PCl_5\rightleftharpoons PCl_3+Cl_2$

Initially

2.5 mol 0 0

At equilibrium:

(2.5 - x) mol x x

So, from above, the moles of phosphorus trichloride at equilibrium , x= 0.338 mol

Mass of 0.338 moles of phosphorus trichloride at equilibrium:

= 0.338 mol × 137.5 g/mol = 46.475 g

Moles of phosphorus pentachloride present at equilibrium :

= (2.5 - 0.338) mol = 2.162 mol

Mass of 2.162 moles of phosphorus pentachloride at equilibrium:

= 2.162 mol × 208.5 g/mol = 450.777 g

Moles of chloride gas present at equilibrium : 0.338 mol

Mass of 0.338 moles of chloride gas at equilibrium:

= 0.338 mol × 71 g/mol = 23.998 g

3 0

3 years ago

Find ∆G for a cell whose potential is +0.24 V with 4 moles of electrons exchanged.

Setler [38]

We need to use the following formula
Δ $G= -nF E_{cell}$

$E_{cell}= 0.24V$
n= 4 moles
F= constant= 96500C/mol

let's plug in the values.

ΔG= -(4)(96500)(0.24)= -92640 J or -92.6 kJ

6 0

3 years ago

Read 2 more answers

The numerator is the blank number in a fraction, while the denominator is the blank number in a fraction

tigry1 [53]

The top number of a portion is called its numerator whereas the bottom number is its denominator. So a Fraction is the quantity of shaded parts separated by the quantity of a balance of as demonstrated as follows: number of shaded parts is the numerator over the whole part which is the denominator.

8 0

3 years ago

An automobile tire contains air at 320.×103 Pa at 20.0 ◦C. The stem valve is removed and the air is allowed to expand adiabatica

NISA [10]

Answer:

6.15.3 k

Explanation:

From the question we can see that

q = 0, Δu = w

Then,

$T_f = \frac{C_{V,m}+RP_{ext}P_i}{C_{V,m}+RP_{ext}P_f} T_i$

putting values wet

= $\frac{2.5\times 8.314+8.314\left(10^5\right)\left(3.20\times 10^5\right)}{2.5\times 8.314+\left(8.314\right)\left(10^5\right)\left(10^5\right)}\times \:293$

T_f = 615.3 K

6 0

3 years ago