The conjugate base of ch3ch2co2h or propanoic acid would be CH3CH2COO- or propanoate. The conjugate base is what is left after an acid has donated a proton in a reaction. Hope this answers the question. Have a nice day.
The volume% of acetone = Ml of acetone/Ml of solution x100
ml of acetone =200ml
ml of solution = 1.60 x1000=1600ml
volume% of acetone is therefore= 200/1600 x100= 12.5%
Answer:
D
Explanation:
plz mark brainliest answer if it helps
Answer:
option A is correct a bond formed by transfer of electron
Answer:
21.88mL is the volume of base required for the titration.
Explanation:
For an acid-base titration trying to find the concentration of an acid, you must add a known quantity of the acid and titrate it with an standarized base.
If you know the moles of base you add to the acid solution, these moles are equal to moles of acid.
In the buret of the titration, initial volume is 1.94mL and final volume is 23.82mL. The volume you are adding is the difference between initial and final volume, that is:
23.82mL - 1.94mL
<h3>21.88mL is the volume of base required for the titration.</h3>
