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1 year ago

You hav to watch the video i don’t understand number 1 what to do help

Chemistry

1 answer:

UkoKoshka [18]1 year ago

5 0

Ok so u js watch the video and go thru tbh e instructions and follow directions

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In an exothermic reaction, the energy of the reactants is greater than the energy of

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Answer:

Explanation:

If the energy content in the reactants is higher than the products, that means that the reaction must be giving away energy. So, in other words, chemical energy from the reactants must be released as heat.

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2 years ago

Whag is the answer. please i need help

icang [17]

Answer:

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Students 1 and 2 have precise measures yet is is not accurate since they measure around 5.

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3 years ago

When 2.00 g of methane are burned in a bomb calorimeter, the change in temperature is 3.08°C. The heat capacity of the calorimet

melisa1 [442]

Answer:

The approximate molar enthalpy of combustion of this substance is -66 kJ/mole.

Explanation:

First we have to calculate the heat gained by the calorimeter.

$q=c\times \Delta T$

where,

q = Heat gained = ?

c = Specific heat = $2.68 kJ/^oC$

ΔT = The change in temperature = 3.08°C

Now put all the given values in the above formula, we get:

$q=2.68 kJ/^oC\times 3.08^oC$

$q=8.2544 kJ$

Now we have to calculate molar enthalpy of combustion of this substance :

$\Delta H_{comb}=-\frac{q}{n}$

where,

$\Delta H_{comb}$ = enthalpy change = ?

q = heat gained = 8.2544kJ

n = number of moles methane = $\frac{\text{Mass of methane}}{\text{Molar mass of methane }}=\frac{2.00 g}{16.042 g/mol}=0.1247 mole$

$\Delta H_{comb}=-\frac{8.2544 kJ}{0.1247 mole}=-66.21 kJ/mole\approx -66 kJ/mole$

Therefore, the approximate molar enthalpy of combustion of this substance is -66 kJ/mole.

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2 years ago

Mole ratio of co2 carbonate to water

tino4ka555 [31]

Pls make ur question alittle clearer by may be saying the chemical compound or writing the required reaction

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3 years ago

What type of particles move to create electicity?<br> electrons<br> protons<br> neutrons

sladkih [1.3K]

the answer is electrons.....

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3 years ago