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solong [7]
3 years ago
9

Determine whether the points (–3,–2) and (3,2) are in the solution set of the system of inequalities below. y ≤ ½x + 2 y < –2

x – 3
Mathematics
1 answer:
lana [24]3 years ago
7 0

Given:

The system of inequalities:

y\leq \dfrac{1}{2}x+2

y

To find:

Whether the points (–3,–2) and (3,2) are in the solution set of the given system of inequalities.

Solution:

A point is in the solution set of the given system of inequalities if it satisfies both inequalities.

Check for the point (-3,-2).

-2\leq \dfrac{1}{2}(-3)+2

-2\leq -1.5+2

-2\leq 0.5

This statement is true.

-2

-2

-2

This statement is also true.

Since the point (-3,-2) satisfies both inequalities, therefore (-3,-2) is in the solution set of the given system of inequalities.

Now, check for the point (3,2).

2

2

2

This statement is false because 2>-9.

Since the point (3,2) does not satisfy the second inequality, therefore (3,2) is not in the solution set of the given system of inequalities.

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Answer:

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Step-by-step explanation:

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1/3 x 2 = 2/3.

12 + 2 = 14.

It will take her 14 months.

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kirill115 [55]

Answer:

(-6,-4)

Step-by-step explanation:

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3 years ago
Which shape has exactly two pairs of perpendicular sides?
Papessa [141]
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6 0
3 years ago
Read 2 more answers
Given right triangle MNL what is the value of cos(M)?
FromTheMoon [43]

Step 1

<u>Find the length of the side MN</u>

we know that

Applying the Pythagorean Theorem

ML^{2} =NL^{2} +MN^{2}

Solve for MN

MN^{2}=ML^{2} -NL^{2}

in this problem

ML=25\ units\\ NL=15\ units

Substitute in the formula above

MN^{2}=25^{2} -15^{2}

MN^{2}=400

MN=20\ units

Step 2

<u>Find the value of cos (M)</u>

we know that

in the right triangle MNL

cos (M)=\frac{adjacent\ side\ angle\ M}{hypotenuse}

adjacent\ side\ angle\ M=MN=20\ units\\ hypotenuse=ML=25\ units

Substitute

cos (M)=\frac{20}{25}

cos (M)=\frac{4}{5}

cos (M)=0.8

therefore

The answer is

The value of cos(M) is equal to 0.8


6 0
3 years ago
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