Answer:
4.27%
Step-by-step explanation:
We have been given that college students average 8.6 hours of sleep per night with a standard deviation of 35 minutes. We are asked to find the probability of college students that sleep for more than 9.6 hours.
We will use z-score formula to solve our given problem.
![z=\frac{x-\mu}{\sigma}](https://tex.z-dn.net/?f=z%3D%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D)
z = z-score,
x = Random sample score,
= Mean,
= Standard deviation.
Before substituting our given values in z-score formula, we need to convert 35 minutes to hours.
![35\text{ min}=0.58\text{ Hour}](https://tex.z-dn.net/?f=35%5Ctext%7B%20min%7D%3D0.58%5Ctext%7B%20Hour%7D)
![z=\frac{9.6-8.6}{0.58}](https://tex.z-dn.net/?f=z%3D%5Cfrac%7B9.6-8.6%7D%7B0.58%7D)
![z=\frac{1}{0.58}](https://tex.z-dn.net/?f=z%3D%5Cfrac%7B1%7D%7B0.58%7D)
![z=1.72](https://tex.z-dn.net/?f=z%3D1.72)
Now, we need to find
.
Using formula
, we will get:
![P(z>1.72)=1-P(z](https://tex.z-dn.net/?f=P%28z%3E1.72%29%3D1-P%28z%3C1.72%29)
Using normal distribution table, we will get:
![P(z>1.72)=1-0.95728](https://tex.z-dn.net/?f=P%28z%3E1.72%29%3D1-0.95728)
![P(z>1.72)=0.04272](https://tex.z-dn.net/?f=P%28z%3E1.72%29%3D0.04272)
![0.04272\times 100\%=4.272\%](https://tex.z-dn.net/?f=0.04272%5Ctimes%20100%5C%25%3D4.272%5C%25)
Therefore, 4.27% of college students sleep for more than 9.6 hours.
Answer:
what is the question, true or false?
Step-by-step explanation:
Answer:
fourth and fifth
Step-by-step explanation:
If George gets a 20% raise, that means he will now earn
$445 + $445*20% = $445 + $445*0.2 = $445*1 + $445*0.2 = $445*(1 + 0.2) = $445 * 1.2
So we know the fourth is correct.
We also know that current pay is 100% of current pay and the new pay will be 120% of current pay, so x/455 must be equal to 120% / 100% which is equal to 120/100, so fifth is correct too.
"more" means added to, or addition. So 8 more than 'x' is:
x + 8