3.2n=3.2*5
3.2*5=16 the answer is 16
Hope this helps, have a great day!!
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Let r(cos O + i sin O) be a cube root of 125(cos 288 + i sin 288)
then
r^3(cos O + i sin O)^3 = 125(cos 288 + i sin 28)
so r^3 = 125 and cos 3O + i sin 3O = cos 288 + i sin 288
so r = 5 and 3O = 288 + 360p and O = 96 + 120p
so one cube root is 5 (cos 96 + i sin 96)
Im a little rusty at this stuff Its been a long time.
Im not sure of the other 2 roots
sorry cant help you any more
Answer:
52
Step-by-step explanation:
1st term is =60-8=52
a2=60-16=44
a3=60-24=36
a4=60-32=28
a5=60-40=20
a6=60-48=12
....
sI the terms are 52,44,36,28, 20,12,4,-4,-12....
so the largest term is 52
2z +7 = -5
2z = -5 -7
2z = -12
z= -12 /2
z= -6
