Answer:
A
Step-by-step explanation:
The x- coordinate of each point ( the domain ) maps to exactly 1 unique y- coordinate ( the range).
This means the situation given represents a function → A
Answer:
A
Step-by-step explanation:
(y-5) / (7-5) = (x-1) / (2-1)
(y-5) / 2 = x-1
y-5 = 2x -2
y = 2x +3
Answer:8-oz jar
First, we have to find out what is the unit rate of the 2-oz jar. $1.50÷2 is $.75.
Second, we have to find the unit rate of the 4-oz jar. $2.92÷4=$73.
Third, we have to find the unit rate of the 8-oz jar. $5.68=$.71.
Fourth, we have to find the unit rate of the 16-oz jar. The division for this one may be tricky. From dividing $11.62 by 16, is stopped at the 3rd number I got from dividing. I got $.726. This is not a value of cents and the value can't go in the thousandths place. So, I rounded .726. I got $.73. So $11.62÷16=$.73.
Lastly, you have to compare the amounts.
The lowest amount or better buy, is $.71 or 8-oz jar.
Answer:
49
Step-by-step explanation:
The area of a triangle is
A = 1/2 bh
A = 1/2 (14)*7
A =49
Given:

To find:
The simplified fraction.
Solution:
Step 1: Simplify the numerator

Step 2: Simplify the denominator

Step 3: Using step 1 and step 2

Step 4: Using fraction rule:


Cancel the common factor r and t², we get

Cancel the common factors 16 and 3 on both numerator and denominator.



The simplified fraction is
.