1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Yakvenalex [24]
3 years ago
14

The spacing between two closely spaced oppositely charged parallel plates is decreased. What happens to the electrostatic potent

ial difference between the plates, assuming they form an isolated system: (a) it increases, (b) it decreases, (c) it stays the same, or (d) you can’t tell from the information given?
Physics
1 answer:
erastovalidia [21]3 years ago
5 0
<h2>Electrostatic Potential Decreases</h2>

Explanation:

  • If the spacing between two closely spaced oppositely charged parallel plates is decreased the electrostatic potential difference between the plates will decrease.
  • An electrostatic potential that is also referred to as the electric field potential or potential drop is the amount of work required to replace a unit of charge from a reference point to a specific point inside the electric field without any change in acceleration.  
  • Therefore, if the distance will decrease between oppositely charged plates there will be more affinity to attract which will reduce the amount of work done thus decreasing the electric potential

∴  The Correct option is (b)

You might be interested in
By what factor must we increase the amplitude of vibration of an object at the end of a spring in order to double its maximum sp
strojnjashka [21]

Answer:

A'=2A

Explanation:

According to the law of conservation of energy, the total energy of the system can be expresed as the sum of the potential energy and kinetic energy:

E=U+K=\frac{kA^2}{2}\\E=\frac{kx^2}{2}+\frac{mv^2}{2}=\frac{kA^2}{2}

When the spring is in its equilibrium position, that is x=0, the object speed its maximum. So, we have:

\frac{k(0)^2}{2}+\frac{mv_{max}^2}{2}=\frac{kA^2}{2}\\A^2=\frac{mv_{max}^2}{k}\\A=\sqrt{\frac{mv_{max}^2}{k}}

In order to double its maximum speed, that is v'{max}=2v_{max}. We have:

A'=\sqrt{\frac{m(v'_{max})^2}{k}}\\A'=\sqrt{\frac{m(2v_{max})^2}{k}}\\A'=\sqrt{\frac{4mv_{max}^2}{k}}\\A'=2\sqrt{\frac{mv_{max}^2}{k}}\\A'=2A

6 0
3 years ago
A cup of coffee sits on the dashboard of an automobile. Even though you hold the cup still, as the car goes around a sharp curve
jasenka [17]
This would be Newton’s first law :)
3 0
3 years ago
Read 2 more answers
Generate description of the right hand rule for finding the magnetic field around a current carrying wire an tell how it is used
vladimir1956 [14]

Answer:

Right hand thumb rule : It is a rule used to find the magnetic field direction around current carrying wire .

Explanation:

It states that : "If you grasp conductor in your right hand such that thumb points in upward direction ,then the direction in which our finger curls gives the direction of magnetic field or magnetic lines of forces" .

This rule proves that :Current can give rise to magnetism .

Around every current carrying conductor there exist a magnetic field which can be easily felt .

According to this rule : When a current flows in upward direction ,the finger curls in anticlockwise direction and when direction of current reverses ,then the direction of field also reverses .

4 0
3 years ago
Hydroelectric power plants can generate huge amounts of electricity. Which of these statements best describes the impact of a hy
Zarrin [17]
The best answer is that it reduces the level of ground water
7 0
3 years ago
Read 2 more answers
The quantity of charge Q in coulombs (C) that has passed through a point in a wire up to time t (measured in seconds) is given b
Mnenie [13.5K]

Explanation:

The quantity of charge Q in coulombs (C) that has passed through a point in a wire up to time t (measured in seconds) is given by :

Q=t^3-2t^2+4t+4

We need to find the current flowing. We know that the rate of change of electric charge is called electric current. It is given by :

I=\dfrac{dQ}{dt}\\\\I=\dfrac{d(t^3-2t^2+4t+4)}{dt}\\\\I=3t^2-4t+4

At t = 1 s,

Current,

I=3(1)^2-4(1)+4\\\\I=3\ A

So, the current at t = 1 s is 3 A.

For lowest current,

\dfrac{dI}{dt}=0\\\\\dfrac{d(3t^2-4t+4)}{dt}=0\\\\6t-4=0\\\\t=0.67\ s

Hence, this is the required solution.

7 0
3 years ago
Other questions:
  • The number of protons and neutrons in an atom is that atom’s _____________ number.
    7·2 answers
  • When fat comes in contact with sodium hydroxide, it produces soap and glycerin. Determine whether this is a physical change or a
    13·2 answers
  • Find change of velocity for:<br> 0-1.7 s<br> 1.7-6s
    8·1 answer
  • Calculate the electric field (in V/m) between two parallel plates connected to a 45 V battery if the plates are separated by a)
    15·2 answers
  • Two asteroids collide and stick together. The first asteroid has mass of 1.50 × 104 kg andis initially moving at 0.77 × 103 m/s.
    5·1 answer
  • A car traveling at 37m/s starts to decelerate steadily. It comes to a complete stop in 15 seconds. What is it’s acceleration
    15·1 answer
  • A speedboat is moving at a rate of 45 km per hour travels a distance of 27 km. How long did it take to go to 27 km.
    15·1 answer
  • A roller coaster car with a mass of 17,690 kg is moving at a speed of 5 m/s over a hill that is 87.4 m above the
    13·1 answer
  • Explain why a metal box does not fall through a table to the floor???
    8·1 answer
  • What is the charge of an electron and charge of neutron
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!