Ask question

Ask question

All categories

2 years ago

8

Hamburgers are sold in packages of 20, while buns are sold in packages of 12. What are the least numbers of packages you should

buy in order to have the same number of hamburgers and buns?

2 answers:

jolli1 [7]2 years ago

7 0

The answer is 60 ;) got it right

aleksley [76]2 years ago

5 0

Answer:

3 packages of hamburger and 5 packages of bun.

Step-by-step explanation:

3x20=60

5x12=60

You might be interested in

A couch, a love seat, and a chair cost $1565. The couch costs twice as much as the chair, and the love seat costs $400 more than

Brilliant_brown [7]

The answer to the question is 1565÷400=3.9125

6 0

3 years ago

Use AAS to prove the triangles congruent..........

andriy [413]

Hey there, 29levelupchaye2!

Angles B and G are congruent because they are alternate interior angles since they are in between two parallel lines.

Angles ACB and HFG are congruent because they are alternate exterior angles since they are both outside two parallel lines cut by a transversal.

Thank you for using Brainly.
See you soon!

4 0

3 years ago

What is the sum of 2/7 + 2/5 ?<br> please help 10 points and brainlest

omeli [17]

Answer:

2/7 + 2/5=24/35

5 0

2 years ago

Leah deposited $50,000 in the bank. Three years later, she borrowed $40,000 for a new truck. From this description, which is the

NISA [10]

Answer: B. (Leah did not have to provide collateral.)

6 0

2 years ago

What is the volume of the sphere that has a diameter of 3? use 3.14 for pie

aev [14]

Hey ! there

Answer:

<u>1</u><u>1</u><u>3</u><u>.</u><u>0</u><u>4</u><u> </u><u>unit </u><u>cube</u>

Step-by-step explanation:

In this question we are provided with a sphere <u>having</u><u> </u><u>radius </u><u>3 </u><u>units </u>and <u>value </u><u>of </u><u>π </u><u>is </u><u>3.</u><u>1</u><u>4</u><u> </u><u>.</u><u> </u>And we're asked to find the<u> </u><u>volume</u><u> of</u><u> </u><u>sphere</u><u> </u><u>.</u>

For finding volume of sphere , we need to know its formula . So ,

$\qquad \qquad \: \underline{\boxed{ \frak{Volume_{(Sphere)} = \dfrac{4}{3} \pi r {}^{3} }}}$

<u>Where</u><u> </u><u>,</u>

π refers to <u>3.</u><u>1</u><u>4</u>

r refers to <u>radius</u><u> of</u><u> sphere</u>

<u>Sol</u><u>u</u><u>tion </u><u>:</u><u> </u><u>-</u>

Now , we are substituting value of π and radius in the formula ,

$\quad \longrightarrow \qquad \: \dfrac{4}{3} \times 3.14 \times (3) {}^{3}$

Simplifying it ,

$\quad \longrightarrow \qquad \: \dfrac{4}{3} \times 3.14 \times 3 \times 3 \times 3$

Cancelling 3 with 3 :

$\quad \longrightarrow \qquad \: \dfrac{4}{ \cancel{3}} \times 3.14 \times 3 \times 3 \times \cancel{3}$

We get ,

$\quad \longrightarrow \qquad \:4 \times 3.14 \times 9$

Multiplying 4 and 3.14 :

$\quad \longrightarrow \qquad \:12.56 \times 9$

Multiplying 12.56 and 9 :

$\quad \longrightarrow \qquad \: \pink{\underline{\boxed{\frak{113.04 \: unit \: cube}}}} \quad \bigstar$

<u>Henceforth</u><u> </u><u>,</u><u> </u><u>volume</u><u> </u><u>of</u><u> </u><u>sphere</u><u> </u><u>having </u><u>radius </u><u>3 </u><u>units </u><u>is </u><em><u>1</u></em><em><u>1</u></em><em><u>3</u></em><em><u> </u></em><em><u>.</u></em><em><u>0</u></em><em><u>4</u></em><em><u> </u></em><em><u>units </u></em><em><u>cube </u></em><em><u>.</u></em>

<h2><u>#</u><u>K</u><u>e</u><u>e</u><u>p</u><u> </u><u>Learning</u></h2>

5 0

1 year ago