<h2>
Answer:</h2>
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Step-by-step explanation:</h2>
For a better understanding of this problem, see the figure below. Our goal is to find 
. Since:
and is a common side both for ΔMRN and ΔMQN, then by SAS postulate, these two triangles are congruent and:
By Pythagorean theorem, for triangle NQP:
Applying Pythagorean theorem again, but for triangle MQN:
y = A(Bx - C)ⁿ + D
A is a vertical stretch (or shrink if |A| < 1)
B is a vertical shrink (or stretch if |B| < 1)
C is a shift to the right (or left if C is negative) → notice that Bx - C is "-C" so to take the opposite
D is a shift up (or down if D is negative)
when C = -3, it is a shift to the left 3 units
when D = -7, it is a shift down 7 units
Answer: B
Answer: Each bow needs 4.67 yards of ribbon.
Step-by-step explanation:
We know that each roll has 20 yd.
She used 3 + 1/2 rolls, then the total length used will be (3 + 1/2) times the length of each roll, this is:
(3 + 1/2)*20 yd = (6/2 + 1/2)*20yd = (7/2)*20yd = 70 yd.
With tose 70 yards of ribbon, she made 15 bows, then the length of ribbon used in each bow will be equal to the quotient between the total length used and the number of ribbons made with it, this is:
70yd/15 = 4.67 yards
Each bow needs 4.67 yards of ribbon.
She has been gone 52 min.
57 - 5 = 52
