Answer:
The surface area of the rectangular pyramid is 
Step-by-step explanation:
we know that
The surface area of the rectangular prism is equal to the area of the rectangular base plus the area of the four triangular faces
so
![SA=(8)(5)+2[14.75]+2[\frac{1}{2}(8)(5)]](https://tex.z-dn.net/?f=SA%3D%288%29%285%29%2B2%5B14.75%5D%2B2%5B%5Cfrac%7B1%7D%7B2%7D%288%29%285%29%5D)
If you've started pre-calculus, then you know that the derivative of h(t)
is zero where h(t) is maximum.
The derivative is h'(t) = -32 t + 96 .
At the maximum ... h'(t) = 0
32 t = 96 sec
t = 3 sec .
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If you haven't had any calculus yet, then you don't know how to
take a derivative, and you don't know what it's good for anyway.
In that case, the question GIVES you the maximum height.
Just write it in place of h(t), then solve the quadratic equation
and find out what 't' must be at that height.
150 ft = -16 t² + 96 t + 6
Subtract 150ft from each side: -16t² + 96t - 144 = 0 .
Before you attack that, you can divide each side by -16,
making it a lot easier to handle:
t² - 6t + 9 = 0
I'm sure you can run with that equation now and solve it.
The solution is the time after launch when the object reaches 150 ft.
It's 3 seconds.
(Funny how the two widely different methods lead to the same answer.)
The answer is from AL2006
Same would need to get at least a 95% on the next test, if he would like to receive a total average of an 80%
L=length W=width
perimeter=2Lx2W
196=2L+2W
Length can be written as 6W because it is 6 times the width. We then substitute this in so all the terms are the same
196=2(6W)+2W
196=12W+2W
196=14W
W=14cm
L= (14x6) 84cm
Answer:
The answer is -1.
Step-by-step explanation:
You have to apply gradient formula :
So you will have to substitute the coordinates into the equation. Let (x1,y1) be (-3,4) and (x2,y2) be (5,-4) :
