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den301095 [7]
3 years ago
7

Pleaseeee help me ASAP.

Mathematics
1 answer:
alekssr [168]3 years ago
5 0

Answer:

m = -2

Step-by-step explanation:

Slope formula ---

m = y2-y1/x2-x1

m = 5-9/8-6

m = -4/2

m = -2

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Anyone know how to do this
Oxana [17]

Answer:

9 sqrt(2) /2 = PQ

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

sin theta = opp/ hypotenuse

sin 45 = PQ = 9

9 sin 45 = PQ

9 sqrt(2) /2 = PQ

4 0
3 years ago
Read 2 more answers
ALGEBRA 2!!!!!!!HELP
Inessa [10]

Answer:

x = - 1, x = - 11

Step-by-step explanation:

Given

2| x + 6 | - 4 = 6 ( add 4 to both sides )

2|x + 6 | = 10 ( divide both sides by 2 )

| x + 6 | = 5

The absolute value function always gives a positive result, but the expression inside can be positive or negative, that is

x + 6 = 5 or - (x + 6) = 5

solve both

x + 6 = 5 ( subtract 6 from both sides )

x = - 1

or

- (x + 6) = 5 , that is

- x - 6 = 5 ( add 6 to both sides )

- x = 11 ( multiply both sides by - 1 )

x = - 11

8 0
3 years ago
Answer these two questions
valina [46]

Answer:

5. Conjecture because you have to make a proof that it is true

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Step-by-step explanation:

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5 0
2 years ago
The equation 3/x=5/7 is equivalent to the equation
katrin2010 [14]

Answer:

Step-by-step explanation:

3/x=5/7 is the same as A 21=5x Both equal to 21/5 or 4 1/5

7 0
3 years ago
Find the absolute maximum and minimum values of the following function on the given interval. If there are multiple points in a
Bond [772]

f(x)=3\sin x+3\cos x\implies f'(x)=3\cos x-3\sin x

f has critical points where f'=0:

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where n is any integer. We get solutions in the interval \left[0,\frac\pi3\right] for n=0, for which x=\frac\pi4.

At this critical point, we have f\left(\frac\pi4\right)=3\sqrt2\approx4.243.

At the endpoints of the given interval, we have f(0)=3 and f\left(\frac\pi3\right)=\frac{3+3\sqrt3}2\approx4.098.

So we have the extreme values

\max\limits_{x\in\left[0,\frac\pi3\right]}f=3\sqrt2

\min\limits_{x\in\left[0,\frac\pi3\right]}f=3

8 0
3 years ago
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