Question

PLEASE HELP ME

Answer 1

Given that,

Electrical energy of the motor = 2280 J

Kinetic energy = 1606 J

Wasted energy in thermal and sound energy = 550 J

To find,

The efficiency of the motor in percent.

Solution,

Efficiency is defined as the ratio of useful output energy to the total energy.

Total energy = 2280 J

Useful energy = 1606 J

$\eta=\dfrac{1606}{2280}\times 100\\\\=70.43\%$

So, the efficiency of the motor is 70.43%.