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Aleks [24]
3 years ago
6

What is the relationship between the kinetic energy of molecules in an object and the object temperature

Physics
1 answer:
andrew11 [14]3 years ago
7 0

I think it might be friction

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9. The three types of stress that act on Earth's rocks are compression, tension, and A. strain. B. shear. C. tephra. D. shale.
Evgen [1.6K]
<span>The three main types of stress in a rock are shearing, tension, and compression. hope. that helped</span>
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3 years ago
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An example of an atom that has no charge is one that has?
Pavlova-9 [17]

Answer: Equal number of protons and electrons. Example: an atom of oxygen atom  has 8 electrons and 8 protons and is neutral.

Explanation:

An atom that has no charge is a neutral atom. It contains electrons equal to protons. For example: A neutral atom of oxygen has 8 protons and 8 electrons.

An atom which has charge is said be ionized. It is either positively charged or negatively charged. It is positively charge when the number of electrons is less than the number of protons. For example: Na^+ contains 10 electrons and 11 protons.

And when the number of electrons is greater than the number of protons, the atom is negatively charged. For example, Cl^- has 17 protons and 18 electrons. It readily accepts an electron to complete its octet.

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The layer of leaves that blocks most of the sunlight from reaching the ground in the rain forest is called the _____.
love history [14]
The answer should be <span>canopy.</span>
4 0
3 years ago
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A playground merry-go-round has a mass of 115 kg and a radius of 2.50 m and it is rotating with an angular velocity of 0.520 rev
tatuchka [14]

Answer:

W_f = 2.319 rad/s

Explanation:

For answer this we will use the law of the conservation of the angular momentum.

L_i = L_f

so:

I_mW_m = I_sW_f

where I_m is the moment of inertia of the merry-go-round, W_m is the initial angular velocity of the merry-go-round, I_s is the moment of inertia of the merry-go-round and the child together and W_f is the final angular velocity.

First, we will find the moment of inertia of the merry-go-round using:

I = \frac{1}{2}M_mR^2

I = \frac{1}{2}(115 kg)(2.5m)^2

I = 359.375 kg*m^2

Where M_m is the mass and R is the radio of the merry-go-round

Second, we will change the initial angular velocity to rad/s as:

W = 0.520*2\pi rad/s

W = 3.2672 rad/s

Third, we will find the moment of inertia of both after the collision:

I_s = \frac{1}{2}M_mR^2+mR^2

I_s = \frac{1}{2}(115kg)(2.5m)^2+(23.5kg)(2.5m)^2

I_s = 506.25kg*m^2

Finally we replace all the data:

(359.375)(3.2672) = (506.25)W_f

Solving for W_f:

W_f = 2.319 rad/s

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3 years ago
Help for physical science u4 limiting reactants
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The reactants are on the left and the products are on the right of the equation
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