3 years ago

Find the area of the trapezoid. Answer without units.

Mathematics

1 answer:

Leto [7]3 years ago

5 0

Answer:

180

Step-by-step explanation:

Since the type of trapezoid is not listed, I cannot really explain, sorry :/

You might be interested in

What is mesure of <MEF

Harrizon [31]

I think you forgot to add a photo

6 0

3 years ago

A bag contains 56 marbles: 7 red, 8 green, 1l yellow, 17 brown, and 13 blue.

Thepotemich [5.8K]

Answer:

oh i've done this. 8/56 so .14 percent i think

Step-by-step explanation:

3 0

2 years ago

Is the following graph<br> an example of a linear<br> function?<br> Yes<br> No

oksian1 [2.3K]

Answer:

Step-by-step explanation:

A linear equation is a straight line.

6 0

3 years ago

The weights of 67 randomly selected axles were found to have a variance of 3.85. Construct the 80% confidence interval for the p

VLD [36.1K]

Answer:

$3.13$

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 67

Variance = 3.85

We have to find 80% confidence interval for the population variance of the weights.

Degree of freedom = 67 - 1 = 66

Level of significance = 0.2

Chi square critical value for lower tail =

$\chi^2_{1-\frac{\alpha}{2}}= 51.770$

Chi square critical value for upper tail =

$\chi^2_{\frac{\alpha}{2}}= 81.085$

80% confidence interval:

$\dfrac{(n-1)S^2}{\chi^2_{\frac{\alpha}{2}}} < \sigma^2 < \dfrac{(n-1)S^2}{\chi^2_{1-\frac{\alpha}{2}}}$

Putting values, we get,

$=\dfrac{(67-1)3.85}{81.085} < \sigma^2 < \dfrac{(67-1)3.85}{51.770}\\\\=3.13$

Thus, (3.13,4.91) is the required 80% confidence interval for the population variance of the weights.

8 0

3 years ago

A video store charges a monthly membership fee of $7.50, but the charge to rent each movie is only $1.00 per movie. Another stor

Zepler [3.9K]

7.50 +1x =2.50x

x= movies
x=5

8 0

3 years ago