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Pavlova-9 [17]
2 years ago
8

Consider the Graph. a. Determine four lines of symmetry for the graph. b. How many other lines of symmetry does this graph posse

ss? c. What other type of symmetry does this graph posses​

Mathematics
1 answer:
ANEK [815]2 years ago
8 0

Answer:

Step-by-step explanation:

a). Lines of symmetry of the circle given in the picture are,

   x = 0

   y = 0

   y = -x

   y = x

b). Since, a circle has infinite lines of symmetry (diameters) so the other lines of symmetry of the given circle will be all infinite numbers of the diameters.

c). Other symmetry this circle has a point symmetry.

  (Looks the same when rotated by 180°).

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Which of the following equations has a graph PARALLEL to the line y = 4x + 7
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y = 4x - 2

Step-by-step explanation:

This equation has the same slope as the equation given which means that they are parallel lines. This equation also has a y-intercept of -2.

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The number of people arriving for treatment at an emergency room can be modeled by a Poisson process with a rate parameter of si
OverLord2011 [107]

Answer:

a) P(x=3)=0.089

b) P(x≥3)=0.938

c) 1.5 arrivals

Step-by-step explanation:

Let t be the time (in hours), then random variable X is the number of people arriving for treatment at an emergency room.

The variable X is modeled by a Poisson process with a rate parameter of λ=6.

The probability of exactly k arrivals in a particular hour can be written as:

P(x=k)=\lambda^{k} \cdot e^{-\lambda}/k!\\\\P(x=k)=6^k\cdot e^{-6}/k!

a) The probability that exactly 3 arrivals occur during a particular hour is:

P(x=3)=6^{3} \cdot e^{-6}/3!=216*0.0025/6=0.089\\\\

b) The probability that <em>at least</em> 3 people arrive during a particular hour is:

P(x\geq3)=1-[P(x=0)+P(x=1)+P(x=2)]\\\\\\P(0)=6^{0} \cdot e^{-6}/0!=1*0.0025/1=0.002\\\\P(1)=6^{1} \cdot e^{-6}/1!=6*0.0025/1=0.015\\\\P(2)=6^{2} \cdot e^{-6}/2!=36*0.0025/2=0.045\\\\\\P(x\geq3)=1-[0.002+0.015+0.045]=1-0.062=0.938

c) In this case, t=0.25, so we recalculate the parameter as:

\lambda =r\cdot t=6\;h^{-1}\cdot 0.25 h=1.5

The expected value for a Poisson distribution is equal to its parameter λ, so in this case we expect 1.5 arrivals in a period of 15 minutes.

E(x)=\lambda=1.5

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Answer:

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Read 2 more answers
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