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n200080 [17]
2 years ago
11

Enter the measurement with the indicated number of significant digits.

Mathematics
1 answer:
Vladimir79 [104]2 years ago
3 0
I think the answer is 2575.8m^2
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Answer please! i will give brainliest !!!!
Damm [24]
The correct answer is b :)
4 0
2 years ago
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Please help me, I need help so bad. make sure to write the full calculation please. If you want bonus points please answer the s
cluponka [151]

Answer:

1. About 9 left. 2. £21 left

Step-by-step explanation:

First, you do 65 ÷ 3 = 21.7 if rounding to the tenths, 21.67 if to the hundredths, and so on. Then you do 21.67 - 12 = 9.67. But since it is cards, I would say about 9 left.

First you add the £20 to the £70 to get £90. then you multiply 7×3 to get £21 spent on books. After that, multiply 12×4 to get £48 spent on games. then do 48 + 21 = 69. 90-69= 21.

Here is the equation....

(70+20)-[(7×3)+(12×4)] = £21

6 0
3 years ago
Solve the equation: c + 4c = -90
Liono4ka [1.6K]

Answer:

c= -18

Step-by-step explanation:

c+4c= -90

combine like terms

5c= -90

Divide by 5 on both sides

c= -18

6 0
2 years ago
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Sally runs 3 miles a day how far will she<br> Run in 3 days
ra1l [238]

Answer:

9 miles

Step-by-step explanation:

3 x 3 = 9 miles per day

6 0
2 years ago
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Find the indicated probability.
natka813 [3]

Answer:

C) 0.179

Step-by-step explanation:

Since the trials are independent, this is a binomial distribution:

<u>Recall:</u>

  • Binomial Distribution --> P(k)={n\choose k}p^kq^{n-k}
  • P(k) denotes the probability of k successes in n independent trials
  • p^k denotes the probability of success on each of k trials
  • q^{n-k} denotes the probability of failure on the remaining n-k trials
  • {n\choose k}=\frac{n!}{(n-k)!k!} denotes all possible ways to choose k things out of n things

<u>Given:</u>

  • n=10
  • k=4
  • p^k=0.53^4
  • q^{n-k}=(1-0.53)^{10-4}=0.47^6
  • {n\choose k}={10\choose 4}=\frac{10!}{(10-4)!4!}=210

<u>Calculate:</u>

  • P(4)=(210)(0.53^4)(0.47^6)=0.1786117069\approx0.179

Therefore, the probability that the archer will get exactly 4 bull's-eyes with 10 arrows in any order is 0.179

7 0
2 years ago
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