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3 years ago

What is the molarity of a solution prepared by diluting 43.72 ml of 1.005 M aqueous K2CR2O7 to 500 ml

Chemistry

1 answer:

UNO [17]3 years ago

3 0

Answer:

43.72

Explanation:

that is the answer hope u liked it and I did this already along time ago

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A substance that speeds up a chemical reaction without being part of the chemical change, itself:

allochka39001 [22]

It is known as a catalyst

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3 years ago

How many joules are required for melting 12.8g of ice at 0 degrees Celsius?

tino4ka555 [31]

Answer:

4,270 Joules

Explanation:

The heat of fusion of water is 334 j/g. So, the equation would be (12.8 g)(334 j/g) which comes to 4,270 joules.

Written out that's just twelve point eight times three hundred and thirty four.

4 0

3 years ago

How many liters of 1.0 M HCl do you need to neutralize 2.0 L of 3.0 M NaOH? How many liters of 1.0 M HCl do you need to neutrali

Kruka [31]

Answer:

For 1: The volume of HCl required is 6 L.

For 2: The volume of HCl required is 9 L.

For 3: The volume of sulfuric acid required is 4.5 L.

Explanation:

To calculate the volume of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$ ......(1)

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base

For 1:

We are given:

$n_1=1\\M_1=1M\\V_1=?L\\n_2=1\\M_2=3.0M\\V_2=2.0L$

Putting values in equation 1, we get:

$1\times 1\times V_1=1\times 3\times 2\\\\V_1=6L$

Hence, the volume of HCl required is 6 L.

For 2:

We are given:

$n_1=1\\M_1=1M\\V_1=?L\\n_2=2\\M_2=3.0M\\V_2=1.5L$

Putting values in equation 1, we get:

$1\times 1\times V_1=2\times 3.0\times 1.5\\\\V_1=9L$

Hence, the volume of HCl required is 9 L.

For 3:

To calculate the volume of acid, we use the equation:

$N_1V_1=N_2V_2$

where,

$N_1\text{ and }V_1$ are the normality and volume of acid

$N_2\text{ and }V_2$ are the normality and volume of base

We are given:

$N_1=1.0N\\V_1=?L\\N_2=3.0N\\V_2=1.5L$

Putting values in above equation, we get:

$1.0\times V_1=3.0\times 1.5\\\\V_1=4.5L$

Hence, the volume of sulfuric acid required is 4.5 L.

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3 years ago

21.0g of pure silver have a volume of 2.00cm^3 what is the density of the silver

Nuetrik [128]

Answer:

please mark my answer brainliest

Explanation:

according to the formula...

density =mass/ volume...

density =21.0/2.00=10.5 g/ cm^3

8 0

3 years ago

1. Examples of pure substances are elements and _____. O mixtures O compounds

andrew11 [14]

Answer: Examples of pure substances include iron, aluminum, silver, and gold. Mixtures: Substances that have two or more different particles are mixtures. Examples of mixture include the salt solution which is a 'mixture' of two components, salt, and water.

Explanation:

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3 years ago