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2 years ago

What is the value of all conversion factors that are used in dimensional analysis

Chemistry

2 answers:

IRISSAK [1]2 years ago

4 0

All the conversions have a net value of 1

UkoKoshka [18]2 years ago

3 0

<h3>Answer;</h3>

All conversion factors have a ratio value equal to one

<h3>Explanation;</h3>

Dimensional analysis refers to the process of conversion between various units.
A conversion factor is a ratio that is equal to one, which means that the two values are equal to each other and will help one to change from one unit to another.
Conversion factors allow an individual to change from one unit to another. When using a conversion factor, the beginning unit has to appear on the bottom of the conversion factor.

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2 years ago

Please help me balance: _NaNO3 + _PbO_ ➡️ Pb(NO3)2 + _Na2O

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Answer:

The balanced reaction is given by,

$2NaN(O)3 + PbO$ ⇒ $Pb(NO3)2 + Na2O$

Explanation:

The reaction is as given.

Lets count the number of each elements in the reaction.

In reactant side, number of sodium atoms are 1 , lead are 1, nitrogen are 1 and oxygen are 4.

in product side, number of sodium atoms are 2 , lead are 1 , nitrogen are 2 and oxygen are 7.

So we need to balance sodium and oxygen atoms in the reaction.

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Thus, multiply (NaNO3) by 2.

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2 years ago

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2 years ago

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How many moles of aluminum oxide (Al2O3) can be produced from 12.8 moles of oxygen gas (02)

zhannawk [14.2K]

Answer:

Theoretical Yield

Percent yield

Example stoichiometry problem

How much oxygen can be prepared from 12.25 g KClO3 . (Use molar mass KClO3 = 122.5 g.)

Most stoichiometry problems can be solved using the following steps.

Step 1.

Write and balance the equation for the decomposition of KClO3 with heat (∆). 2KClO3 + ∆ → 2KCl + 3O2

Step 2.

Convert what you have (in this case g KClO3) to moles.

# moles = grams/molar mass = 12.25 g /122.5 = 0.100 mole KClO3.

Step 3.

Using the coefficients in the balanced equation, convert moles of what you have (moles KClO3) to moles of what you want (in this case moles oxygen).

0.100 mol KClO3 x (3 moles O2/2 moles KClO3) = 0.100 x (3/2) = 0.150 mole O2.

Step 4.

Convert moles from step 3 to grams.

moles x molar mass = grams

0.150 mole O2 x (32.0 g O2/mole O2) = 4.80 g O2 produced from 12.25 g KClO3. This is the theoretical yield. If the ACTUAL yield is 4.20 grams, calculate percent yield. Percent yield = (actual yield/theoretical yield) x 100 = (4.20/4.80) x 100 = 87.5% yield

NOTE: In step 1, moles can be obtained other ways; in step 4 moles can be converted to other units.

a. For solutions, M x L = moles (or mL x M = millimoles).

b. For gases, L/22.4 = moles

4 0

2 years ago

Instead of 6 M NaOH being added to the solution, 6 M HCl is added. How will this affect the test for the presence of ammonium io

Lera25 [3.4K]

Answer:

Ammonia gas(an alkaline gas with characteristics of choking or irritating smell) is not liberated when 6mole of HCl is added to the solution instead of 6mole of NaOH, to test for the presence of ammonium ion in the solution

Explanation:

As expected, when testing for ammonium ion in a solution (precisely ammonium salt solution), Sodium Hydroxide (NaOH) is required as the test reagent.

When NaOH is added to the solution, A gas with characteristics of choking or irritating smell is liberated.

This gas turn red litmus paper blue.

This liberated gas is an alkaline gas, which is confirmed as an ammonia gas(NH3).

If HCl is added instead of NaOH, the ammonia gas will not be liberated, which indicates that the test reagent used is wrong.

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2 years ago