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katen-ka-za [31]
3 years ago
7

What is the value of all conversion factors that are used in dimensional analysis

Chemistry
2 answers:
IRISSAK [1]3 years ago
4 0
All the conversions have a net value of 1
UkoKoshka [18]3 years ago
3 0
<h3><u>Answer;</u></h3>

All conversion factors have a ratio value equal to one

<h3><u>Explanation;</u></h3>
  • <em><u>Dimensional analysis refers to the process of conversion between various units.</u></em>
  • <em><u>A conversion factor is a ratio that is equal to one, which means that the two values are equal to each other and  will help one to change from one unit to another.</u></em>
  • Conversion factors allow an individual to change from one unit to another. When using a conversion factor, the beginning unit has to appear on the bottom of the conversion factor.
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Which statement correctly describes potassium iodide, KI? There is a one-to-one ratio of potassium ions to iodide ions. Potassiu
elena-14-01-66 [18.8K]

The answer is there is a one-to-one ratio of potassium ions to iodide ions.

Explanation :

- (K) belongs to Alkali metals in group (1A) that contains (1) electron in the outermost energy level, whereas, (I) is from halogens in group (7A) that contains (7) electron in the outermost energy level.

- To achieve stability, both atoms tend to reach the nearest noble state (outermost level occupies 8 electrons). Therefore, (K) loses its outer electron and gives it to (I) which now has a completely filled outer level and an ionic bond is formed between the two.

- The valency (number of electrons lost, gained or shared) of both atoms is equal ”monovalent” which means one-to-one ratio..


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3 years ago
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3 years ago
29. What is E for a system which has the following two steps:
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Answer:

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Explanation:

Recall that;

E = q + w

Where;

q = heat, w = work done

When heat is absorbed by the system q is positive

When heat is evolved by the system q is negative

When the system does work, w is negative

When work is done on the system w is positive

Step 1

ΔE1= 60 KJ + 40 KJ = 100KJ

Step 2

ΔE2= (-30 KJ) + (-70 KJ) = (-100) KJ

ΔE1 + ΔE2= 100KJ + (-100) KJ = 0KJ

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