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adoni [48]
3 years ago
15

which of these pieces of equipment would be the most appropriate for precisely measuring 29 mL of liquid? Explain your reasoning

, citing evidence related to the divisions on each tool and the concept of an estimated digit.​

Chemistry
1 answer:
Anna007 [38]3 years ago
5 0

Answer:

The best equipment would be the graduated cylinder. Why?

Firstly, the smallest marking on the graduated cylinder is 2 mL, while on all the others the smallest marking is way above that, like 25 mL and 100 mL.

Without even going into the details, we can first rule out the volumetric flask, since its smallest marking is 100 mL and even that is already bigger than our sample size, hence we would have no markings to accurately measure out 29 mL of our sample had we used the volumetric flask.

Next to be ruled out would be the Erlenmeyer flask, as you can see in the image, it only has three marking, and as the smallest marking is 25 mL, each marking is at least 25 mL, and even so far as going up to 50 mL. This cannot let us accurately measure 29 mL out at all, due to the markings being way too big to do that. Hence, the Erlenmeyer flask is ruled out.

Finally, the beaker seems to be a worthy candidate! Unfortunately, for the same reason as the Erlenmeyer flask, as you can see in the image each marking represents 10 mL. We cannot measure 9 mL in the beaker accurately, and hence the beaker is ruled too.

We are left with the graduated cylinder, and that is our answer.

Explanation:

Hope this helped!

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How many moles of CO2 must dissolve in excess water to produce 12 moles of<br><br> H2CO3?
vodka [1.7K]

Answer:

12 moles of CO₂.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

CO₂ + H₂O —> H₂CO₃

From the balanced equation above,

1 mole of CO₂ dissolves in water to produce 1 mole of H₂CO₃.

Finally, we shall determine the number of moles of CO₂ that will dissolve in water to produce 12 moles of H₂CO₃. This can be obtained as follow:

From the balanced equation above,

1 mole of CO₂ dissolves in water to produce 1 mole of H₂CO₃.

Therefore, 12 moles of CO₂ will also dissolve in water to produce 12 moles of H₂CO₃.

Thus, 12 moles of CO₂ is required.

3 0
3 years ago
Calculate the concentration of hi when the equilibrium constant is 1x10^5
exis [7]
Answer is: concentration of hydrogen iodide is 6 M.

Balanced chemical reaction: H₂(g) + I₂(g) ⇄ 2HI(g).
[H₂] = 0.04 M; equilibrium concentration of hydrogen.
[I₂] = 0.009 M; equilibrium concentration of iodine.
Keq = 1·10⁵.
Keq = [HI]² / [H₂]·[I₂].
[HI]² = [H₂]·[I₂]·Keq.
[HI]² = 0.04 M · 0.009 M · 1·10⁵.
[HI]² = 36 M².
[HI] = √36 M².
[HI] = 6 M.
5 0
3 years ago
How many grams of sodium are needed to produce 12.5g of sodium oxide
Hatshy [7]

Answer:

25 possibly

Explanation:

I'm not too sure about this, but sodium oxide is Na2O, 2 sodium and 1 oxygen, so 12.5g * 2 is 25

If someone else comes up with a more convincing argument listen to them

4 0
3 years ago
Which is most often used to destroy bacteria?
vovangra [49]
Iodine- in most cleaning solutions
7 0
3 years ago
The table above shows the number of protons in an Adam of four different elements according to the periodic table which of these
Maurinko [17]

Answer:

<u>The correct answer is X</u>

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Explanation:

First have some idea about : Valency , Metals and non- metals.

Valency : It is the combining capacity of elements . The elements combine to other elements to gain stability . They always try to complete their octet(8 electrons in the outermost shell)

For Example : Na has 11 electron

Its electronic configuration is : 2 ,8 ,1 (2+8+1 = 11)

First shell contain maximum = 2 electron

2nd shell = maximum 8 electron

3 shell = maximum 18 electron

When it remove 1 electron from outermost shell , it is left with 2 ,8 configuration. Now , its outer most shell has 8 electron . so it get stable and show +1 valency.

When the element looses electron , it get positive charge

When the element gain electron it get negative charge

Metals: those element which show +1 , +2 , +3 valency are considered as metals

Non- metals = Those metals which show the valency of -1 , -2 ,-3 are considered as Non- Metals.

Questions:

1. T = 7 proton

Electronic configuration = 2 , 5

It gains (-ve charge) 3 electron to achieve complete octet(5+3 = 8) = -3 valency

It is non- metal

2. Q=15

Its electronic configuration = 2 ,8 , 5

It gains (-ve charge) 3 electron to achieve complete octet(5+3 = 8) = -3 valency

It is non- metal

3.X = 12

Its electronic configuration = 2 ,8 , 2

It loses (+ve charge) 2 electron to achieve complete octet( 2 , 8) = + 2 valency

It is  metal

4.Z = 17

Its electronic configuration = 2 ,8 , 7

It gains (-ve charge) 1 electron to achieve complete octet(7+1 = 8) = -1 valency

It is non- metal

<u>There is only one metal = X</u>

4 0
3 years ago
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