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adoni [48]
3 years ago
15

which of these pieces of equipment would be the most appropriate for precisely measuring 29 mL of liquid? Explain your reasoning

, citing evidence related to the divisions on each tool and the concept of an estimated digit.​

Chemistry
1 answer:
Anna007 [38]3 years ago
5 0

Answer:

The best equipment would be the graduated cylinder. Why?

Firstly, the smallest marking on the graduated cylinder is 2 mL, while on all the others the smallest marking is way above that, like 25 mL and 100 mL.

Without even going into the details, we can first rule out the volumetric flask, since its smallest marking is 100 mL and even that is already bigger than our sample size, hence we would have no markings to accurately measure out 29 mL of our sample had we used the volumetric flask.

Next to be ruled out would be the Erlenmeyer flask, as you can see in the image, it only has three marking, and as the smallest marking is 25 mL, each marking is at least 25 mL, and even so far as going up to 50 mL. This cannot let us accurately measure 29 mL out at all, due to the markings being way too big to do that. Hence, the Erlenmeyer flask is ruled out.

Finally, the beaker seems to be a worthy candidate! Unfortunately, for the same reason as the Erlenmeyer flask, as you can see in the image each marking represents 10 mL. We cannot measure 9 mL in the beaker accurately, and hence the beaker is ruled too.

We are left with the graduated cylinder, and that is our answer.

Explanation:

Hope this helped!

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Now, based on the formula above     P = (nRT) ÷ V
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Answer:

  • <em><u>2I ⁻ → I₂ + 2e⁻</u></em> describes the <em><u>oxidation.</u></em>

  • <u><em>Cl₂ + 2e⁻ → 2Cl ⁻</em></u> describes the <u><em>reduction</em></u>.

Explanation:

<em>Oxidation-reduction reaction</em> is the simulaneous oxidation and reduction of the substances and is represented by two half-reactions.

The <em>oxidation</em> half-reaction is the loss of electrons, with the consequent increase in the oxidation state by the oxidized substance.

In this case, the process that shows the loss of electrons is:

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That reaction shows:

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  • The change in the oxidation number is from -1 to 0.
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On the other hand, the <em>reduction</em> half-reaction is the gain of electrons, with the consequent reduction of the oxidation state by the reduced substance.

In this case, the process that shows the gain of electrons is:

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That reaction shows:

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  • The change in the oxidation number is from 0 to - 1.
  • Hence, this half-reaction is the reduction reaction.

<u>Summary:</u>

  • <em>2I ⁻ → I₂</em> + 2e⁻ describes the oxidation.

  • <em>Cl₂ + 2e⁻ → 2Cl ⁻</em> describes the reduction.
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