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ruslelena [56]
3 years ago
14

What is the mass of 20 buckets

Mathematics
2 answers:
Margarita [4]3 years ago
5 0
10 percent is the mass number
Olenka [21]3 years ago
4 0
20xmass of one bucket
You might be interested in
What polynomial should be subtracted from 7x2−6x+5 to get the difference equal to x2−x.
Karolina [17]

Answer:

6x^2-5x+5 should be subtracted.

Step-by-step explanation:

we find the polynomial that is subtracted from 7x^2-6x+5 to get the difference equal to x^2-x

7x^2-6x+5-polynomial=x^2-x

To get the polynomial subtract x^2-x from the given polynomial

7x^2-6x+5 - (x^2-x)=  7x^2-6x+5-x^2+x

6x^2-5x+5

So 6x^2-5x+5 should be subtracted.

8 0
4 years ago
This is for anyone who has ever been cheated on before...
Evgen [1.6K]

Answer:

thank you

Step-by-step explanation:

4 0
3 years ago
Solve similar triangles <br> Solve for x <br> x=?
lions [1.4K]

Answer:

x/9 = 1/5

x = 9/5

6 0
3 years ago
Xample 2
valentina_108 [34]

Answer:

Median: 17

Q1: 10

Q3: 23

Step-by-step explanation:

2, 4, 9, 11, 12, 16,   18, 20, 22, 24, 28, 32

Median is middle number/average of the 2 middle numbers. 16 + 18 = 34/2 = 17

First/lower quartile/Q1 = middle of lower half of ordered data set

= 9 + 11 = 20/2 = 10

Third/upper quartile/Q3 = middle of upper half of ordered data set

= 22 + 24 = 46/2 = 23

Sorry if this is too late. Posting it will probably save someone else, though.

6 0
3 years ago
On average, Tanner has noticed that 22 trains pass by his house daily (24 hours) on the nearby train tracks. What is the probabi
blondinia [14]

Answer:

0.11069

Step-by-step explanation:

We will assume that the trains pass by his house following a uniform distribution with values between 0 and 24. The probability of a train passing on a 9-hour time period is 9/24 = 3/8 = 0.375. Lets call Y the amount of trains passing by his house during that 9-hour period. Y follows a Binomail distribution with parameters 22 and 0.375.

P(Y ≤ 5) = P(Y = 0) + P(Y=1) + P(Y=2) + P(Y=3) + P(Y=4) + P(Y=5) =

{22 \choose 0} * 0.375^0*(1-0.375)^{22} + {22 \choose 1}*0.375^1*(1-0.375)^{21} +\\\\{22 \choose 2} * 0.375^2*(1-0.375)^{20} + {22 \choose 3}*0.375^3*(1-0.375)^{19}  + \\{22 \choose 4} * 0.375^4*(1-0.375)^{18} + {22 \choose 5}*0.375^5*(1-0.375)^{17} = 0.11069

I hope that works for you!

4 0
3 years ago
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