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Solnce55 [7]
3 years ago
15

A jet travels 460 miles in 2 hours. Atb this rate , how far could the jet fly in 11 hours? What is the rate of speed of the jet

?
Mathematics
1 answer:
USPshnik [31]3 years ago
5 0

Answer:

230 MPH

2530 Miles

460miles/2 hours= 230 mph

230x11= 2530

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Kruka [31]

Answer:

the answer is forty sevan

Step-by-step explanation:

104 - 57 equals 47

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3 years ago
Given A(2,0) and B(8,4), show that P(3,5) is on the perpendicular bisector of line AB by these 2 methods
Shalnov [3]

1) First we need to find midpoint M of segment AB.

... M = (A+B)/2 = ((2+8)/2, (0+4)/2) = (5, 2)

Then vector AB is B-A = (8-2, 4-0) = (6, 4)

and vector PM is P-M = (3-5, 5-2) = (-2, 3)

The latter has slope that is 3/-2 = -3/2. The former has slope that is 4/6 = 2/3.

The product of these slopes is -1, indicating these vectors are perpendicular.

2) Vector PA is P-A = (3-2, 5-0) = (1, 5).

Vector PB is P-B = (3-8, 5-4) = (-5, 1).

The lengths of both of these vectors are √(1²+5²) = √26.

7 0
3 years ago
According to a Pew Research Center, in May 2011, 35% of all American adults had a smart phone (one which the user can use to rea
Veronika [31]

Answer:

p_v =P(z>1.82)=0.034  

Assuming a standard significance level of \alpha=0.05 the best conclusion for this case would be:

4. There is not enough evidence to show that more than 35% of community college students own a smart phone (P-value = 0.034).

Because p_v

If we select a significance level lower than 0.034 then the conclusion would change.

Step-by-step explanation:

Data given

n=300 represent the random sample taken

X=120 represent the people who have a smart phone

\hat p=\frac{120}{300}=0.4 estimated proportion of people who have a smart phone

p_o=0.35 is the value that we want to test

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

System of hypothesis

We need to conduct a hypothesis in order to test the claim that the true proportion of people who have a smart phone is higher than 0.35, the system of hypothesis are.:  

Null hypothesis:p\leq 0.35  

Alternative hypothesis:p > 0.35  

The statistic is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.4 -0.35}{\sqrt{\frac{0.35(1-0.35)}{300}}}=1.82  

Statistical decision  

Since is a right tailed test the p value would be:  

p_v =P(z>1.82)=0.034  

Assuming a standard significance level of \alpha=0.05 the best conclusion for this case would be:

4. There is not enough evidence to show that more than 35% of community college students own a smart phone (P-value = 0.034).

Because p_v

If we select a significance level lower than 0.034 then the conclusion would change.

4 0
3 years ago
Show that a sequence {sn} coverages to a limit L if and only if the sequence {sn-L} coverages to zero.
Andreyy89

Let {s_n}_{n\in\Bbb N} be a sequence that converges to L. This means for any \varepsilon>0, there is some N such that |s_n-L| for all n>N. From this inequality we see that |(s_n-L)-0|, so it follows that s_n-L\to0.

On the other hand, let {s_n-L} be a sequence that converges to 0. This means |(s_n-L)-0| for all large enough n, and we get the simpler inequality for free, |s_n-L|, so it follows that s_n\to L.

3 0
3 years ago
F(x) = x3 + 3x² - 4x
Nezavi [6.7K]

Answer:

x(x−1)(x+4)

Step-by-step explanation: there are no like terms

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