Question

A manufacturing firm tests job applicants. Test scores are normally distributed with a mean of 500 and a standard deviation of 50. What is the probability that the candidate score is 600 or greater

Answer 1

Answer:

The probability that the candidate score is 600 or greater

P(X≥ 600 ) = 0.0228

Step-by-step explanation:

Step(i):-

Given mean of the Population = 500

Given standard deviation of the Population = 50

Let 'X' be the random variable in normal distribution

Given  X = 600

$Z = \frac{x-mean}{S.D} = \frac{600-500}{50} = \frac{100}{50} =2$

Step(ii):-

The probability that the candidate score is 600 or greater

P(X≥ 600 ) = P(z≥2)

                  = 0.5 - A(2)

                 = 0.5 -0.4772

                = 0.0228

Final answer:-

The probability that the candidate score is 600 or greater

P(X≥ 600 ) = 0.0228