Electrical kettle:
P = 2 KW = 2000 W
U = 200 V
⇒ I = P/U = 2000 / 200 = 10 A
We apply the Law of Ohm:
R = U / I = 200V / 10A = <u>20 Ω</u>
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Electrical heater:
P = 1 KW = 1000 W
U = 240 V
⇒ I = P/U = 1000 / 240 = 4,16 A
We apply the Law of Ohm:
R = U / I = 240V / 4,16A = <u>57,69 Ω</u>
<u>Answer:</u>
The device with the highest resistance is <u>the electric heater.</u>
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Answer:
Explanation:
Given that, .
R = 12 ohms
C = 500μf.
Time t =? When the charge reaches 99.99% of maximum
The charge on a RC circuit is given as
A discharging circuit
Q = Qo•exp(-t/RC)
Where RC is the time constant
τ = RC = 12 × 500 ×10^-6
τ = 0.006 sec
The maximum charge is Qo,
Therefore Q = 99.99% of Qo
Then, Q = 99.99/100 × Qo
Q = 0.9999Qo
So, substituting this into the equation above
Q = Qo•exp(-t/RC)
0.9999Qo = Qo•exp(-t / 0.006)
Divide both side by Qo
0.9999 = exp(-t / 0.006)
Take In of both sodes
In(0.9999) = In(exp(-t / 0.006))
-1 × 10^-4 = -t / 0.006
t = -1 × 10^-4 × - 0.006
t = 6 × 10^-7 second
So it will take 6 × 10^-7 a for charge to reached 99.99% of it's maximum charge
If 1 second = 10000 μs
what about how many seconds = 0.77 μs
the calculations would be done lke this
0.77 x 1/1000000 = 7.7 x 10 ^ -7
Speed = distance / time
distance = length of the spacecraft
therefore speed = 250/7.7 x 10^ -7
ans = 324675324.7 m/s
Answer : B - real
Explanation : 1. you can see the image the way it is as in its no in a mirror.
2. The image will not be inverted
But it could be magnified too tbh. But I would go for real
