Explanation:
Force between two charges is given by
where q₁ and q₂ are charges and r is the distance between them.
Here one charge is doubled with keeping all others same.
q₁ = 2 q₁
We have
Magnitude of force doubles.
Answer:
a.) 20 km east
b.) 50 km west
c.) 80 km west
Explanation:
As given,
Railway station - A B C
Distance(km) - 0 30 60
Starts from A , train reaches B be in 15 minutes
Starts from A , train reaches C be in 30 minutes
a.)
If A is origin
As train covers 30km = 15 minutes
⇒ 15 minutes = 30 km
1 minute = km
⇒ 10 minutes = 2×10 = 20 km
∴ we get
The position of the train moving from station A to station B after 10 minutes = 20 km east
b.)
If B is origin then , the position of the train moving from station A to station B after 10 minutes = 30 + 20 = 50 km west
( Because B is the origin , so firstly train go from B to A in 15 minutes ( 30 km ) then A to B in 10 minutes (20 km) )
c.)
If C is the origin then , the position of the train moving from station A to station B after 10 minutes = 60 + 20 = 80 km west
( Because C is the origin , so firstly train go from C to A in 30 minutes ( 60 km ) then A to B in 10 minutes (20 km) )
The figure is missing: find it in attachment.
a) (3i - 5j) N
First of all, we have to write each force as a vector with a direction:
- Force F1 points downward, so along the negative y-direction, so we can write it as
- Force F2 points to the right, so along the positive x-direction, so we can write it as
- Force F3 points to the left, so along the negative x-direction, so we can write it as
Now we can write the net force, by adding the three vectors and separating the x-component from the y-component:
b) 5.8 N
The magnitude of the net force can be calculated by applying Pythagorean's theorem on the components of the net force:
where
is the x-component
is the y-component
Substituting into the equation,
c)
The angle of the net force, measured with respect to the positive x-axis (counterclockwise), can be calculated by using the formula
where
is the x-component
is the y-component
Substituting into the equation, we find
d)
The acceleration can be found by using Newton's second law:
where
F is the net force on an object
m is its mass
a is the acceleration
For the object in the problem, we know
F = 5.8 N
m = 6.9 kg
Solving the equation for a, we find the magnitude of the acceleration:
