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2 years ago

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Anders suffered a shock when his electric radio dropped into the bathtub--while anders was taking a bath. Anders argued that he

did not realize it was dangerous to operate an electric radio near his bathtub. If he sues the radio manufacturer for damages, which claim is he most likely to make?.

1 answer:

blsea [12.9K]2 years ago

3 0

The claim Anders is most likely to make is the failure of the manufacturer to warn about such risk.

<h3>What is a Risk?</h3>

This is defined as the possibility of something bad happening and in this case it is electric shock when dropped into the bathtub.

Anders can decide to sue for not warning against risk of electric shock when in contact with water.

Read more about Risk here brainly.com/question/1224221

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Why is the following situation impossible? A skater glides along a circular path. She defines a certain point on the circle as h

Arturiano [62]

Answer:

A skater glides along a circular path. She defines a certain point on the circle as her origin. Later on, she passes through a point at which the distance she has traveled along the path from the origin is smaller than the magnitude of her displacement vector from the origin.

So here in circular motion of the skater we can see that the total path length of the skater is along the arc of the circle while we can say that displacement is defined as the shortest distance between initial and final position of the object.

So it is not possible in any circle that arc-length is less than the chord joining the two points on the circle

As we know that arc length is given as

$L = R\theta$

length of chord is given as

$L_c = 2Rsin(\frac{\theta}{2})$

so here

$L > L_c$

$R\theta > 2R sin(\frac{\theta}{2})$

so we have

$\frac{\theta}{2} > sin(\frac{\theta}{2})$

6 0

2 years ago

A factory worker pushes a 30.0-kg crate a distance of 4.5 m along a level floor at constant velocity by pushing horizontally on

SIZIF [17.4K]

(a) 73.5 N

The velocity of the crate is constant: this means that the acceleration is zero (a=0), so according to Newton's second law

$\sum F = ma$

the resultant of the forces must be zero: $\sum F = 0$ (1)

The motion is along the horizontal direction, so we are only interested in the forces acting along this direction. There are two of them:

$F$ , the push applied by the worker

$F_f=-\mu mg$ , the force of friction, with $\mu=0.25$ being the coefficient of friction, $m=30.0 kg$ being the mass of the crate, and $g=9.8 m/s^2$ . The negative sign is due to the fact that the friction acts in the opposite direction to the motion. Eq.(1) then becomes

$F-\mu mg=0\\F=\mu mg=(0.25)(30.0 kg)(9.8 m/s^2)=73.5 N$

So, this is the force that the worker must apply.

(b) 330.8 J

The work done by the pushing force of the worker on the crate is given by:

$W=Fd cos \theta$

where

F = 73.5 N is the force

d = 4.5 m is the displacement

$\theta=0^{\circ}$ is the angle between the direction of the force and the displacement (0 degrees, since they are in same direction)

Substituting, we have

$W=(73.5 N)(4.5 m)(cos 0^{\circ})=330.8 J$

(c) -330.8 J

To calculate the work done by friction, we apply the same formula:

$W=F_f d cos \theta$

where

$F_f = \mu mg=(0.25)(30.0 kg)(9.8 m/s^2)=73.5 N$ is the magnitude of the force of friction

d = 4.5 m is the displacement

$\theta=180^{\circ}$ is the angle between the direction of the force of friction and the displacement (it is 180 degrees since the two are into opposite directions)

Substituting, we find

$W=(73.5 N)(4.5 m)(cos 180^{\circ})=-330.8 J$

So, the work done by friction is negative.

(d) 0 J

As before, the work done by any force on the crate is

$W=F_f d cos \theta$

We notice that both gravity and normal force are perpendicular to the displacement: therefore, $\theta=90^{circ}$ , and so

$cos \theta=0$

which means that the work done by both forces is zero.

(e) 0 J

The total work done on the crate is the sum of the work done by the four forces acting on it, so:

$W=W_{push} + W_{friction}+W_{gravity}+W_{normal}=330.8J-330.8J+0+0=0$

And this is in accordance with the work-energy theorem, which states that the variation of kinetic energy of the crate is equal to the work done on it: since the crate is moving at constant velocity, its variation of kinetic energy is zero, as well as the work done on it.

5 0

2 years ago

timama [110]

Answer:

A

Explanation:

The acceleration of an object is directly proportional to its net force.

$a = \frac{f}{m}$

4 0

3 years ago

Read 2 more answers

2. (1 point) Two metal spheres with different radii are each hanging from insulating nylon threads. One of the spheres has a net

DiKsa [7]

Answer:

A. attract each other

Explanation:

When the neutral sphere is brought close to the negatively charged, as charges can move freely in a conductor, some electrons will be repelled, leaving a net positive charge (equal in magnitude ot the charge in the other sphere) on the surface of the neutral sphere, which will cause that both spheres attract each other.

6 0

3 years ago

What is the kinetic energy of a 144 gram baseball moving at a velocity of 38.7 meters per second?

gulaghasi [49]

Answer:

The kinetic energy of the baseball is 107.83 J

Explanation:

Given;

mass of the baseball, m = 144 g = 0.144 kg

velocity of the baseball, v = 38.7 m/s

The kinetic energy of the baseball is given by;

K.E = ¹/₂mv²

where;

m is mass of the object

v is speed of the object

K.E = ¹/₂(0.144)(38.7)²

K.E = 107.83 J

Therefore, the kinetic energy of the baseball is 107.83 J

8 0

2 years ago