All categories

2 years ago

If F(theta)=tan theta=3, find F(theta+pi)

Physics

1 answer:

Alex_Xolod [135]2 years ago

4 0

The period of the tan function is π so (∅ + π) would yield the same value as ∅
F(∅ + π) = 3

You might be interested in

Which of the following most accurately describes the current understanding of energy? *

Stolb23 [73]

Answer:

Explanation:

Because it is the principle of conservation of energy which is proved and verified

6 0

3 years ago

Which action can be explained by physics ?

LiRa [457]

The pressure of blood exerted on the inner walls of the veins

8 0

3 years ago

Read 2 more answers

A school bus transporting students to school is an example of

jok3333 [9.3K]

Answer:

The answer is D. If I got this right will you please mark me as Brainliest.

3 0

3 years ago

Read 2 more answers

Problem 1: Two sources emit waves that are coherent, in phase, and have wavelengths of 26.0 m. Do the waves interfere constructi

Anton [14]

1) Destructive interference

The condition for constructive interference to occur is:

$\delta = m\lambda$ (1)

where

$\delta =|d_1 -d_2|$ is the path difference, with

$d_1$ is the distance of the point from the first source

$d_2$ is the distance of the point from the second source

m is an integer number

$\lambda$ is the wavelength

In this problem, we have

$d_1 = 78.0 m\\d_2 = 143 m\\\lambda=26.0 m$

So let's use eq.(1) to see if the resulting m is an integer

$\delta =|78.0 m-143 m|=65 m\\m=\frac{\delta }{\lambda}=\frac{65 m}{26.0 m}=2.5$

It is not an integer so constructive interference does not occur.

Let's now analyze the condition for destructive interference:

$\delta = (m+\frac{1}{2})\lambda$ (2)

If we apply the same procedure to eq.(2), we find

$m=\frac{\delta}{\lambda}-\frac{1}{2}=\frac{65.0 m}{26.0 m}-0.5=2$

which is an integer: so, this point is a point of destructive interference.

2) Constructive interference

In this case we have

$d_1 = 91.0 m\\d_2 =221.0 m$

So the path difference is

$\delta =|91.0 m-221.0 m|=130.0 m$

Using the condition for constructive interference:

$m=\frac{\delta }{\lambda}=\frac{130.0 m}{26.0 m}=5$

Which is an integer, so this is a point of constructive interference.

3) Destructive interference

In this case we have

$d_1 = 44.0 m\\d_2 =135.0 m$

So the path difference is

$\delta =|44.0 m-135.0 m|=91.0 m$

Using the condition for constructive interference:

$m=\frac{\delta }{\lambda}=\frac{91.0 m}{26.0 m}=3.5$

This is not an integer, so this is not a point of constructive interference.

So let's use now the condition for destructive interference:

$m=\frac{\delta}{\lambda}-\frac{1}{2}=\frac{91.0 m}{26.0 m}-0.5=3$

which is an integer: so, this point is a point of destructive interference.

3 0

3 years ago

The fastest pitched baseball was clocked at 46 m/s. assume that the pitcher exerted his force (assumed to be horizontal and cons

Zielflug [23.3K]

Using the Equation:
v² = vi² + 2 · a · s → Eq.1
where,
v = final velocity
vi = initial velocity
a = acceleration
s = distance

We know that vi = 0 because the ball was at rest initially.

Therefore,

Solving Eq.1 for acceleration,

 v² = vi² + 2 · a · s
v² = 0 + 2 · a · s
v² = 2 · a · s
Rearranging for a,
a = v ²/2·s
Substituting the values,
a = 46²/2×1
a = 1058 m/s²

Now applying Newton's 2nd law of motion,

F = ma
= 0.145×1058

F = 153.4 N

8 0

3 years ago