Profit (P) is calculated by subtracting the total cost (C) from the total revenue (R). The calculations are shown below,

R = (1440 dozens) x (12 pieces / 1 dozen) x (25 cents/ piece) = $4320
C = (1440 dozens) x ($2.50 / dozen) = $3600

Profit = R - C = $4320 - $3600 = $720

Thus, the businessman's profit is $720.

7 0

3 years ago

During a tunnel construction project, engineers used explosives to excavate partway into a mountain. Because of time constraints

AnnyKZ [126]

The given data can be tabulated as:

number of days,x length of tunnel (ft), y

0 225

5 350

20 725

30 975

55 1,600

To check if the growth is linear, the slope at points (0, 225) and (5, 350), and (0, 225) and (20, 725) should be equal. The formula for slope is:

m = (y2 – y1) / (x2 – x1)

Finding for slope (0, 225) and (5, 350):

m = (350 – 225) / (5 – 0) = 25

Finding for slope (0, 225) and (20, 725):

m = (725 – 225) / (20 – 0) = 25

Therefore the equation is linear in the form of:

y = mx + b

where b is the value of y at x = 0, so b = 225

The complete equation is:

y = 25x + 225

At x = 86 days

y = 25(86) + 225

y = 2,375 ft

Therefore the length of the completed tunnel is 2,375 feet.

5 0

4 years ago

I need help to these questions. Convert these fractions to a decimal 7/8 , 4 3/8. Thanks

ehidna [41]

Simple...

you have: $\frac{7}{8}$ and $4 \frac{3}{8}$

Now, the first one is easy just divide it...

$\frac{7}{8} =0.875$

Now....

$4 \frac{3}{8}$ needs to be converted...

Multiply the whole number*denominator...

4*8=32

Now add the numerator....

32+3=35

Now use the original denominator...

$\frac{35}{8}$

Now divide...

$\frac{35}{8}=4.375
$

Thus, your answer.

7 0

3 years ago

Read 2 more answers

Find the fifth term in the sequence<br>that is defined as follows:<br>an = 2n

Rainbow [258]

Answer:

$a_{5}=10$

Step-by-step explanation:

If you want to find the 5th term of a sequence or any term you have to substitute n for the desired term in your case the result is the following

$a_{n}=2n\\a_{5}=2(5)\\a_{5}=10$

7 0

3 years ago