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1 year ago

Simplify and then evaluate the equation when A=2 and b=4

Mathematics

1 answer:

Westkost [7]1 year ago

6 0

we have the equation

$b^2+3(b-b^2)-2a$

Remove the parenthesis and apply the distributive property

$b^2+3b-3b^2-2a$

Combine like terms

$-2b^2+3b-2a$

For a=2 and b=4

substitute

$\begin{gathered} -2(4)^2+3(4)-2(2) \\ -32+12-4 \\ -24 \end{gathered}$ <h2>the answer is -24</h2>

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WIll give brainliest Use the information given to answer the question.

MaRussiya [10]

Answer:

x²-12x+36

Step-by-step explanation:

an expression in the form (a-b)² is expanded to the form a²-2ab+b²

you can also expand it to (x-6)×(x-6) then multiply the first term by the first the outer term by the outer term the inner term by the inner term and the last term by the last term (foil)

the first terms are x and x = x² the outer terms are x and -6 = -6x the inner terms are also x and -6 = -6x

the last terms are 6 and 6 = 36

adding all the four products =

x²-12x+36

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3 years ago

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ddd [48]

Answer:

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Step-by-step explanation:

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3 years ago

Xa/xb = xa-b. This is the______of Powers of property. The word is 8 letters long

SashulF [63]

it might be quantity btw I love your pfp

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3 years ago

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GrogVix [38]

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3 years ago

Please help! question attached

Svetradugi [14.3K]

Answer:

36. y=x

37. x=4

38. y=3x-10

39. y=-25x+49

40. $y=-\dfrac{1}{18}x-\dfrac{89}{18}$

41. y=-x+3

Step-by-step explanation:

36. Parallel lines have the same slope. The slope of the line $y=x+42$ is $m=1,$ so the equation of a parallel line is

$y=x+b$

This line passes through the point (2,2), so its coordinates satisfy the equation:

$2=2+b\\ \\b=0$

and the equation of the line is $y=x$

37. The line $x=03$ is vertical ine, so parallel line is also vertical line with equation $x=a.$ Substitute the coordinates of the point (4,3):

$4=a$

hence the equation is $x=4$

38. Parallel lines have the same slope. The slope of the line $y=3x+24$ is $m=3,$ so the equation of a parallel line is

$y=3x+b$

This line passes through the point (2,-4), so its coordinates satisfy the equation:

$-4=3\cdot 2+b\\ \\b=-10$

and the equation of the line is $y=3x-10$

39. Parallel lines have the same slope. The slope of the line $y=-25x+35$ is $m=-25,$ so the equation of a parallel line is

$y=-25x+b$

This line passes through the point (2,-1), so its coordinates satisfy the equation:

$-1=-25\cdot 2+b\\ \\b=49$

and the equation of the line is $y=-25x+49$

40. Perpendicular lines have slopes satisfying $m_1\cdot m_2=-1$ Since the line $y=18x+26$ has the slope $m_1=18,$ perpendicular line has the slope $m_2 =-\dfrac{1}{18}.$

The equation is

$y=-\dfrac{1}{18}x+b$

This line passes through the point (1,-5), so its coordinates satisfy the equation:

$-5=-\dfrac{1}{18}\cdot 1+b\\ \\b=-5+\dfrac{1}{18}=-\dfrac{89}{18}$

and the equation of the line is $y=-\dfrac{1}{18}x-\dfrac{89}{18}$

41. Perpendicular lines have slopes satisfying $m_1\cdot m_2=-1$ Since the line $y=x+2$ has the slope $m_1=1,$ perpendicular line has the slope $m_2 =-1.$

The equation is

$y=-x+b$

This line passes through the point (4,-1), so its coordinates satisfy the equation:

$-1=-4+b\\ \\b=3$

and the equation of the line is $y=-x+3$

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3 years ago