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3 years ago

6

Rationalize the denominator in the expression.

" id="TexFormula1" title=" \frac{4}{\sqrt{2} } " alt=" \frac{4}{\sqrt{2} } " align="absmiddle" class="latex-formula">

1 answer:

Dovator [93]3 years ago

7 0

Answer:

2 $\sqrt{2}$

Step-by-step explanation:

See the photo for the steps. :)

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The point (3, 6) is on the graph of y= 5f(2(x+3))-4 . Find the original point on the graph of y=f(x).

Sonja [21]

Answer:

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Step-by-step explanation:

<u>Given:</u>

$y= 5f(2(x+3))-4$ has a point <em>(3, 6)</em> on its graph.

<u>To find:</u>

Original point on graph $y=f(x)$ = ?.

<u>Solution:</u>

We are given that The point (3, 6) is on the graph of $y= 5f(2(x+3))-4$

If we put x = 3 and y = 6 in $y= 5f(2(x+3))-4$ , it will satisfy the equation.

Let us the put the values and observe:

$6= 5f(2(3+3))-4\\\Rightarrow 6= 5f(2(6))-4\\\Rightarrow 6= 5f(12)-4\\\Rightarrow 6+4=5f(12)\\\Rightarrow 5f(12)= 6+4\\\Rightarrow 5f(12)= 10\\\Rightarrow f(12)= \dfrac{10}{5}\\\Rightarrow f(12)= 2\\OR\\\Rightarrow 2=f(12)$

Now, let us compare the above with the following:

$y=f(x)$

we get y = 2 and x = 12

So, the original point on graph of $y=f(x)$ is <em>(12, 2).</em>

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