The missing values are 28° and 62°
<h3>What are perpendicular lines?</h3>
Perpendicular lines are said to be two lines that intersect or meet each other at right angles, that is 90 degrees.
From the information given, we have that;
Line AC ⊥ Line BE
Where:
- m ∠ ADE = (x + 5)°
- m ∠ DBE = (3x - 7)°
Hence,
x + 5 + 3x - 7 = 90
collect like terms
4x = 90 + 2
4x = 92
Make 'x' the subject
x = 92/ 4
x = 23
For the missing values
m ∠ ADE = (x + 5)° = ( 23 + 5) = 28°
m ∠ DBE = (3x - 7)° = (3(23) - 7) = 62°
Thus, the missing values are 28° and 62°
Learn more about perpendicular lines here:
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Y=8.50x+5.00
56=y
-56=8.50x+5.00
56=8.50x+5.00
-5.00 -5.00
51=8.50x
÷8.5 ÷8.5
6=x <u>HE CAN BUY 6 DVDS</u>
1. a
2. c
3. b
hope this helps
Answer:
Step-by-step explanation:
Given a general quadratic formula given as ax²bx+c = 0
To generate the general formula to solve the quadratic equation, we can use the completing the square method as shown;
Step 1:
Bringing c to the other side
ax²+bx = -c
Dividing through by coefficient of x² which is 'a' will give:
x²+(b/a)x = -c/a
- Completing the square at the left hand side of the equation by adding the square of half the coefficient x i.e (b/2a)² and adding it to both sides of the equation we have:
x²+(b/a)x+(b/2a)² = -c/a+(b/2a)²
(x+b/2a)² = -c/a+(b/2a)²
(x+b/2a)² = -c/a + b²/4a²
- Taking the square root of both sides
√(x+b/2a)² = ±√-c/a + b²/√4a²
x+b/2a = ±√(-4ac+b²)/√4a²
x+b/2a =±√b²-4ac/2a
- Taking b/2a to the other side
x = -b/2a±√√b²-4ac/2a
Taking the LCM:
x = {-b±√b²-4ac}/2a
This gives the vertex form with how it is used to Solve a quadratic equation.
Answer:
i think its B
Step-by-step explanation:
