Answer:
<u>s</u><u>u</u><u>g</u><u>a</u><u>r</u> is the solute and <u>w</u><u>a</u><u>t</u><u>e</u><u>r</u> is the solvent
Answer: ≈ 67.4 g
Explanation:
A(t) = amount remaining in t years = A0ekt, where A0 is the initial amount and k is a constant to be determined. Since A(1690) = (1/2)A0 and A0 = 80, we have 40 = 80e1690k 1/2 = e1690k ln(1/2) = 1690k k = -0.0004 So, A(t) = 80e-0.0004t Therefore, A(430) = 80e-0.0004(430) = 80e-0.172 ≈ 67.4 g
No. The only thing that changed was the looks of the gasoline, not the chemical components.
Answer:
[A] + [B] decrease rapidly.
[CD] increases rapidly.
Explanation:
<em>A + B → CD,</em>
The reaction proceeds that A reacts with B and their concentration decreases to produce CD that its concentration increases with time.
At the beginning of the reaction; the concentration of A + B decreases rapidly and the concentration of CD increases rapidly.
<em>Kindly, see the attached image.</em>
<em />
[A] + [B] decrease rapidly.
[CD] increases rapidly.
The scale will read <u>112 grams.</u>
Why?
Since we already know the percent error of the scale (12%) and we also know the mass of the block that is placed on the scale, we can calculate what will be the read of the scale by using the following formula:
We can see that the scale will read 112 grams.
Let's verify that we are right by using the following formula to verify if the obtained value for the scale read will be 12%:
Hence, we can see that the scale will read <u>112 grams.</u>
Have a nice day!